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Dmitry_Shevchenko [17]
3 years ago
5

Radioactive was discovered by Albert Einstein Truth or False Need answer

Physics
2 answers:
valkas [14]3 years ago
7 0
Falseness is the correct choice.
Iteru [2.4K]3 years ago
4 0
False .......................
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How will the gravitational force on a piece of the surface of the star (m1) by the mass of the rest of the star (m2) (effectivel
kiruha [24]

Answer:

Option B

Explanation:

Gravitational force is a force that attracts two bodies (with a mass) towards each other. If an object has a higher mass, the gravitational pull will be greater.

According to Newton’s inverse square law:

<em>"The gravitational force is inversely proportional to the square of the distance between two bodies."</em>

About this question, the greater the distance between two gravitating bodies, the weaker is the gravitational force between them.

6 0
3 years ago
Jupiter's moon Io has active volcanoes (in fact, it is the most volcanically active body in the solar system) that eject materia
kramer

Answer:

The height reached by the material on Earth is 91 km.

Explanation:

Given that,

Mass M_{Io}=8.93\times10^{22}\ kg

Radius = 1821 km

Height h_{Io}=500\ km

Suppose we need to find that how high would this material go on earth if it were ejected with the same speed as on Io?

We need to calculate the acceleration due to gravity on Io

Using formula of gravity

g =\dfrac{GM_{Io}}{(R_{Io})^2}

Put the value into the formula

g=\dfrac{6.67\times10^{-11}\times8.93\times10^{22}}{(1821\times10^{3})^2}

g=1.79\ m/s^2

Let  v be the speed at which the material is ejected.

We need to calculate the height

Using the formula of height

H=\dfrac{v^2}{2g}

Using ratio of height of earth and height of Io

\dfrac{H_{e}}{H_{Io}}=\dfrac{\dfrac{v^2}{2g_{e}}}{\dfrac{v^2}{2g_{Io}}}

\dfrac{H_{e}}{H_{Io}}=\dfrac{g_{Io}}{g_{e}}

Put the value into the formula

\dfrac{H_{e}}{H_{Io}}=\dfrac{1.79}{9.8}

\dfrac{H_{e}}{H_{Io}}=0.182

H_{e}=0.182\times H_{Io}

H_{e}=0.182\times500

H_{e}=91\ km

Hence, The height reached by the material on Earth is 91 km.

3 0
3 years ago
Because cosmic distances are so vast, astronomers use light-years as their unit of distance. One light-year is defined as ______
8090 [49]

Answer:

Because cosmic disaster are so vast, astronomers use light-years as their unit of distance. One light-year is defined as <u>the distance a beam of light travels in one year</u>. The nearest star is a little more than <u>4.37 light-years</u> away from us. When we see light from a galaxy 2 million light-years away, it has taken<u> 2 million Earth years</u> to reach us. Light from the Sun takes <u>approximately 8.4269 minutes</u> to reach us

Explanation:

i) One light-year is defined as the distance a light beam travels in a time of one Earth year. One light year is equivalent to 6 × 10¹² miles or 9.7 × 10¹² km

ii) The distance to the nearest star =  4.37 light-years

iii) When a star located in a galaxy that is 2.3 million light years away is seen, it has taken 2.3 million light years to reach us

iv) The distance of the Sun to the Earth = 151.58 million kilometers

The speed of light, c = 299792.458 km/s

The time it will take light to reach us from the Sun, 't', is given as follows;

t = 151.58 × 10⁶ km/(299792.458 km/s) ≈ 8.4269 minutes.

7 0
3 years ago
Two small identical conducting spheres are placed with their centers 0.41 m apart. One is given a charge of 12 ✕ 10−9 C, the oth
nataly862011 [7]

(a) -1.48\cdot 10^{-5}N

The electrostatic force exerted between the two sphere is given by:

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q1, q2 are the charges on the two spheres

r is the separation between the centres of the two spheres

In this problem,

q_1 = 12\cdot 10^{-9} C\\q_2 = -23\cdot 10^{-9} C\\r = 0.41 m

Substituting these values into the equation, we find the force

F=(9\cdot 10^9 Nm^2 C^{-2} )\frac{(12\cdot 10^{-9}C)(-23\cdot 10^{-9} C)}{(0.41 m)^2}=-1.48\cdot 10^{-5}N

And the negative sign means the force is attractive, since the two spheres have charges of opposite sign.

(b) +1.62\cdot 10^{-6}N

The total net charge over the two sphere is:

Q=q_1 +q_2 = 12\cdot 10^{-9}C+(-23\cdot 10^{-9}C)=-11\cdot 10^{-9} C

When the two spheres are connected, the charge distribute equally over the two spheres (since they are identical, they have same capacitance), so each sphere will have a charge of

q=\frac{Q}{2}=\frac{-11\cdot 10^{-9}C}{2}=-5.5\cdot 10^{-9}C

So the electrostatic force between the two spheres will now be

F=k\frac{q^2}{r^2}

And substituting numbers, we find

F=(9\cdot 10^9 Nm^2 C^{-2} )\frac{(-5.5\cdot 10^{-9} C)^2}{(0.41 m)^2}=+1.62\cdot 10^{-6}N

and the positive sign means the force is repulsive, since the two spheres have same sign charges.

7 0
3 years ago
What is the difference between the number of electrons in an atom of Iodine (I) and the number of electrons in an atom of Alumin
o-na [289]

Answer:

Iodine is element number 53. Iodine has 53 protons and 53 electrons (because it has no charge the number of protons equals the number of electrons). Iodine-131 has 131 protons and neutrons.

Explanation:

5 0
2 years ago
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