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3 years ago

14

How did Bohr propose the particles within atom are arranged

2 answers:

Tanya [424]3 years ago

7 0

The correct answer is C. Protons and neutrons form the nucleus of the atom with electrons orbiting it

Explanation:

Bohr model was proposed by Niels Bohr in 1913 to explain the structure of atoms, in this Bohr stated electrons (particles negatively charge) orbit the nucleus that contains both neutrons (neutral particles) and protons (positively charged particles). Additionally, according to this model electrons were placed in different levels of energy and orbit the nucleus constantly, resembling planets in the Solar System, although the Bohr model was the first one that integrated principles related to energy levels and changes in energy in electrons. Thus, Bohr proposed "Protons and neutrons form the nucleus of the atom with electrons orbiting it".

luda_lava [24]3 years ago

5 0

Answer:

Protons and neutrons form the nucleus of the atom with electrons orbiting it.- C.

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lozanna [386]

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3 years ago

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3 years ago

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A Chemist measured 184 mL using a graduated cylinder. Based on her experience, the volume did not seem to be correct. This volum

salantis [7]

Answer:

Percent error = 20%

Explanation:

The percent error is calculated using the following equation:

Percent error = |(approximate value - exact value)| / (exact value) x 100%

In this problem, the approximate value was 184 mL and the exact value was 230.0 mL

Percent error = |(184 mL - 230.0 mL)| / (230.0 mL) x 100% = 20%

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3 years ago

What is the energy required to remove the electron from a hydrogen atom in the n = 11 state?

zaharov [31]

Based on the data given, the energy required to remove an electron from a hydrogen atom in the n = 11 state is -0.112 eV

<h3>What is ionization energy?</h3>

Ionization energy is the energy requiredto remove an electron from a neutral atom or a cation in its gaseous state.

To calculate the energy required to remove the electron from a hydrogen atom in the n = 11 state, the formula below is used:

$E_n = \frac{E_0 × Z^{2}}{n^{2}}$

where

$E_0 \: is \: ground \: state \: energy \: of \: hydrogen \: atom \: = -13.6 eV \\$

Z = 1
n = 11

substituting the values:

$E_n = \frac{ - 13.6 × 1^{2}}{11^{2}} \: = - 0.112 \: eV$

Therefore, the energy required to remove an electron from a hydrogen atom in the n = 11 state is -0.112 eV

Learn more about ionization energy at: brainly.com/question/1445179

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2 years ago

What is the mass in grams of 6.022 x 1023 molecules of CO2?

Kamila [148]

Answer: Molar mass of CO2 is 44 gram/mol. So,the mass of 1 mole or 6.02*10^23 molecules of CO2 is 44 grams

Explanation:

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3 years ago