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beks73 [17]
3 years ago
9

A Chemist measured 184 mL using a graduated cylinder. Based on her experience, the volume did not seem to be correct. This volum

e was again measured using a calibrated standard device, from which it was determined that the volume of the liquid was actually 230.0 mL. What is the % error in this measurement?
Chemistry
1 answer:
salantis [7]3 years ago
8 0

Answer:

Percent error = 20%

Explanation:

The percent error is calculated using the following equation:

Percent error = |(approximate value - exact value)| / (exact value) x 100%

In this problem, the approximate value was 184 mL and the exact value was 230.0 mL

Percent error = |(184 mL - 230.0 mL)| / (230.0 mL) x 100% = 20%

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Answer : The amount of in kilojoules released is, -5.53 kJ

Explanation :

Formula used :

q=m\times c\times (T_{final}-T_{initial})

where,

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Now put all the given values in the above formula, we get:

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5 0
4 years ago
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Answer:

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