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babunello [35]
3 years ago
14

When there are no decomposers, what happens to the grass?

Chemistry
2 answers:
zavuch27 [327]3 years ago
6 0

Answer:

if there would have been no decomposers on Earth, the whole of the Earth would have been filled with dead and decaying matter of plants and animals.

Explanation:

I hope this helps :3

MissTica3 years ago
6 0

Answer:  Imagine what would happen if there were no decomposers. Wastes and the remains of dead organisms would pile up and the nutrients within the waste and dead organisms would not be released back into the ecosystem. Producers would not have enough nutrients.

Explanation:

https://www.ck12.org/biology/consumers-and-decomposers/lesson/Consumers-and-Decomposers-MS-LS/#:~:text=Imagine%20what%20would%20happen%20if,would%20not%20have%20enough%20nutrients.

This is the site I got the info on, just so you know!  I hope this helps!

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Analyse the temperature versus time graph of water, given below.
BlackZzzverrR [31]

Answer:

Phase C - Liquid State

Phase E - Gaseous State

Explanation:

Usually, in phases of water, we have the following;

When temperature is less than zero, it is said to be in its solid phase as ice.

When temperature is between 0 to 100, we can say it is in the liquid phase as water.

When temperature is above 100°C, It is said to be in the gaseous phase as vapour.

From the diagram;

Phase C is the only liquid state because it falls between temperature of 0°C and 100°

Also, only phase E is in the gaseous phase because the temperature is above 100°C.

3 0
2 years ago
Suppose you want to create a 6 ng/μL solution in a 25 mL volumetric flask. However, this concentration cannot really be accurate
Over [174]

Answer:

Mass of chemical = 1.5 mg

Explanation:

Step 1: First calculate the concentration of the stock solution required to make the final solution.

Using C1V1 = C2V2

C1 = concentration of the stock solution; V1 = volume of stock solution; C2 = concentration of final solution; V2 = volume of final solution

C1 = C2V2/V1

C1 = (6 * 25)/ 0.1

C1 = 1500 ng/μL = 1.5 μg/μL

Step 2: Mass of chemical added:

Mass of sample = concentration * volume

Concentration of stock = 1.5 μg/μL; volume of stock = 10 mL = 10^6 μL

Mass of stock = 1.5 μg/μL * 10^6 μL = 1.5 * 10^6 μg = 1.5 mg

Therefore, mass of sample = 1.5 mg

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3 years ago
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The answer is Oregon.
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