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2 years ago

When there are no decomposers, what happens to the grass?

Chemistry

2 answers:

zavuch27 [327]2 years ago

6 0

Answer:

if there would have been no decomposers on Earth, the whole of the Earth would have been filled with dead and decaying matter of plants and animals.

Explanation:

I hope this helps :3

MissTica2 years ago

6 0

Answer: Imagine what would happen if there were no decomposers. Wastes and the remains of dead organisms would pile up and the nutrients within the waste and dead organisms would not be released back into the ecosystem. Producers would not have enough nutrients.

Explanation:

https://www.ck12.org/biology/consumers-and-decomposers/lesson/Consumers-and-Decomposers-MS-LS/#:~:text=Imagine%20what%20would%20happen%20if,would%20not%20have%20enough%20nutrients.

This is the site I got the info on, just so you know! I hope this helps!

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Is nickel cyanide a ionic or covalent bond

dlinn [17]

Answer:

Ionic

Explanation:

Because there's a metal and nonmetal present in this bond, it is ionic. Covalent bonds occur when there are only metals present. Hope this helps.

3 0

2 years ago

For the reaction 2NH3(g) + 2O2(g)N2O(g) + 3H2O(l) H° = -683.1 kJ and S° = -365.6 J/K The standard free energy change for the rea

BlackZzzverrR [31]

Answer:

$\Delta G^{0}$ = -457.9 kJ and reaction is product favored.

Explanation:

The given reaction is associated with 2 moles of $NH_{3}$

Standard free energy change of the reaction ( $\Delta G^{0}$ ) is given as:

$\Delta G^{0}=\Delta H^{0}-T\Delta S^{0}$ , where T represents temperature in kelvin scale

So, $\Delta G^{0}=(-683.1\times 10^{3})J-(273K\times -365.6J/K)=-583291.2J$

So, for the reaction of 1.57 moles of $NH_{3}$ , $\Delta G^{0}=(\frac{1.57}{2})\times -583291.2J=-457883.592J=-457.9kJ$

As, $\Delta G^{0}$ is negative therefore reaction is product favored under standard condition.

6 0

3 years ago

How many electrons will metals generally have in their outer shell

Goshia [24]

Answer:

1 - 3

Explanation:

- Look to see where metals are on the periodic table then look at what group they are in. The group tells you the number of valence electrons. Ex. 1A has one valence electron.

- Hope this helped! If you need a further explanation please let me know.

3 0

2 years ago

How does carbon dioxide behave differently (its properties) as a gas compared with as a solid?

ankoles [38]

It is effected by diffusion (the power of smell and wind spread) but a solid is not.

4 0

2 years ago

Write the empirical formula of at least four binary ionic compounds that could be formed from the following ions: Zn2+, Ni4+, F-

hram777 [196]

Ionic compounds are formed between oppositely charged ions.

A binary ionic compound is composed of ions of two different elements - one of which is a positive ion(metal), and the other is negative ion (nonmetal).

To write the empirical formula of binary ionic compound we must remember that one ion should be positive and other ion should be negative, then only the correct formula should be written. To write the empirical formula the charges of opposite ions should be criss-crossed.

First empirical formula of binary ionic compound is written between $Zn^{2+} (Positive ion)and F^{-} (Negative ion)$

First Formula would be $ZnF_{2}$

Second empirical formula is between $Zn^{2+}(Positive ion) and O^{2-}(Negative ion)$

Second Formula would be $Zn_{2}O_{2}$

Note : When the subscript are same they get cancel out, so $Zn_{2}O_{2}$ would be written as $ZnO$

Third empirical formula is between $Ni^{4+}(Positive ion) and F^{-}(Negative ion)$

Third Formula would be : $NiF_{4}$

Forth empirical formula is between $Ni^{4+}(Positive ion)and O^{2-}(negative ion)$

Forth Formula would be : $Ni_{2}O_{4}$ or $NiO_{2}$

Note- The subscript will be simplified and the formula will be written as $NiO_{2}$ .

The empirical formula of four binary ionic compounds are : $ZnF_{2}, ZnO, NiF_{4},NiO_{2}$

8 0

2 years ago

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