Answer:
The compression in the spring is 9.64 meters.
Explanation:
Given that,
Mass of the train, m = 6251 kg
Speed of the train, v = 27 m/s
Spring constant of the spring, k = 48979 N/m
We need to find the compression in the spring when it comes to rest. It is a case of conservation of energy. The kinetic energy of the train is converted to elastic potential energy. So,
x is compression in spring
So, the compression in the spring is 9.64 meters.
Answer:
C
Explanation:
The order is this: Displacement --> Velocity --> Acceleration. The velocity directly affects the displacement and the acceleration directly affects the velocity. (changing the acceleration changes the velocity which also changes the displacement).
To go forward in our order, find the slope of the curve/line. To go backwards, find the area under the curve/line. In this case, we are trying to find the displacement of the object, so we should find the area of a velocity-time graph.
Answer:
Time = 0.187 secs
Explanation:
Parameters given:
Speed of hot air balloon = 1.60 m/s
Speed of toss = 10.7 m/s
Distance between passenger and friend at time of toss = 2m
To find the time given, we can simply divide the distance between the passenger and her friend by the speed of the toss. Mathematically,
Time = distance/speed
Time = 2/10.7
Time = 0.187 secs
Therefore, it takes 0.187 seconds for the camera to get to her.
<span>So we want to know what factor is affected by the changes of the independant variable. So if we have the form f(x)=x, x would be the independant variable and when we change the value of that variable we directly change the dependant variable, because the value of the dependant variable is dependant of the independant variable. </span>
Answer: When the worker is on the top rung
Explanation: When the ladder was initially resting on the wall, the torque from the normal reaction on ladder from the horizontal surface is equal to the torque from the vertical surface on ladder.
The weight of the worker produces a torque which is in the direction of the torque from the normal reaction on ladder, produced by the vertical surface. Therefore for the ladder to stay in rotational equilibrium, the torque on ladder from the normal reaction produced by the horizontal surface must increase.
This increase is possible when the worker is on the lower rung, but as the worker goes high, the magnitude of normal reaction from the vertical surface would increase, thereby increasing the risk of slipping of ladder.