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Vanyuwa [196]
3 years ago
8

Gaseous ethane reacts with gaseous oxygen gas to produce gaseous carbon dioxide and gaseous water . What is the theoretical yiel

d of water formed from the reaction of of ethane and of oxygen gas? Be sure your answer has the correct number of significant digits in it.
Chemistry
1 answer:
Effectus [21]3 years ago
8 0

Answer:

1) Write the balanced equation:

2C2H6 + 7O2 ---> 4CO2 + 6H2O

2) Determine limiting reagent:

C2H6 ⇒ 13.8 g / 30.0694 g/mol = 0.45894 mol

O2 ⇒ 45.8 g / 31.9988 g/mol = 1.4313 mol

C2H6 ⇒ 0.45894 / 2 = 0.22947

O2 ⇒ 1.4313 / 7 = 0.20447

Oxygen is limiting.

3) Determine theoretical yield of water:

The oxygen : water molar ratio is 7 : 6

7 is to 6 as 1.4313 mol is to x

x = 1.2268286 mol of water

4) Convert moles of water to grams:

1.2268286 mol times 18.015 g/mol = 22.1 g (to three sig figs)

Solution to (b):

14.2 g / 22.1 g = 64.2%

Explanation:

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When sodium carbonate is dissolved in water, the equation is Na_2CO_3 (s) --- > 2Na^+ (aq) + CO_3^{2-} (aq).

When carbon dioxide is placed in water, aqueous carbon dioxide is formed:  CO_2 (g) --- > CO_2(aq)

<h3>Dissolution of compounds in water</h3>

Some compounds are water-soluble, some are just partially soluble, while others are insoluble in water. Some soluble or partially soluble substances dissociate in water into their component ions. These substances are said to be ionic.

Sodium carbonate, like every other sodium salt, is soluble in water. It dissolves in water to form an aqueous solution of sodium carbonate.

While in solution, sodium carbonate dissociates into its component ions according to the following equation:

Na_2CO_3 (s) --- > 2Na^+ (aq) + CO_3^{2-} (aq)

Carbon dioxide, on the other hand, does not dissociate in water. Instead, it dissolves in water where most of it remains as aqueous carbon dioxide in equilibrium with a small amount of hydronium ion and hydrogen carbonate ion.

Since the hydronium and hydrogen carbonate ions formed are so minute, the equation of the reaction can be written as: CO_2 (g) --- > CO_2(aq)

More on the dissolution of substances can be found here: brainly.com/question/28580758

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Compounds A, B, and C react according to the following equation. 3A(g) + 2B(g) 2C(g) At 100°C a mixture of these gases at equili
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Answer:

The value of Kc for the reaction is 3.24

Explanation:

A reversible chemical reaction, indicated by a double arrow, occurs in both directions: reagents transforming into products ( direct reaction) and products transforming back into reagents (inverse reaction)

Chemical Equilibrium is the state in which direct and indirect reactions have the same reaction rate. Then taking into account the rate constant of a direct reaction and its inverse the chemical constant Kc is defined.

Being:

aA + bB ⇔ cC + dD

where a, b, c and d are the stoichiometric coefficients, the equilibrium constant with the following equation:

Kc=\frac{[C]^{c} *[D]^{d} }{[A]^{a} *[B]^{b} }

Kc is equal to the multiplication of the concentrations of the products raised to their stoichiometric coefficients divided by the multiplication of the concentrations of the reagents also raised to their stoichiometric coefficients.

Then, in the reaction 3A(g) + 2B(g) ⇔ 2C(g),  the constant Kc is:

Kc=\frac{[C]^{2} }{[A]^{3} *[B]^{2} }

where:

  • [A]= 0.855 M
  • [B]= 1.23 M
  • [C]= 1.75 M

Replacing:

Kc=\frac{1.75^{2} }{0.855^{3}*1.23^{2}  }

Solving you get:

Kc=3.24

<u><em>The value of Kc for the reaction is 3.24</em></u>

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3 years ago
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