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serg [7]
3 years ago
8

A car travels 25 kilometers in one hour. If it does not change its speed or direction, how far will the car travel in the next h

our?
Physics
1 answer:
Sladkaya [172]3 years ago
3 0

Answer: 25 km

Explanation: If it travels 25 km in 1 hour it is going 25 km/h meaning if its speed doesn't change for the next hour it will go another 25 km.

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A 1460-kg submarine rises straight up towards the surface. Seawater exerts both an upward buoyant force of 16670 N on the submar
Amiraneli [1.4K]

Answer:

a = 0.63 m/s²

Explanation:

given,

mass of submarine = 1460-kg

upward buoyant force = 16670 N

downward resistive force = 1150 N

submarine acceleration = ?

assuming g = 10 m/s²

now,

B - (R + mg) = ma

16670 - 1150 - 1460 × 10 = 1460 × a

1460× a = 920

a = 0.63 m/s²

hence, the acceleration of submarine is equal to a = 0.63 m/s²

5 0
3 years ago
Who’s has bigger cross sectional area capillaries or aorta?
Natalka [10]

Answer:

Even though the cross-sectional area of each capillary is extremely small compared to that of the large aorta, the total cross-sectional area of all the capillaries added together is about 1,300 times greater than the cross-sectional area of the aorta because there are so many capillaries

Explanation:

8 0
2 years ago
EXPERTS/ACE and people that wanna help 4 sure only!
mario62 [17]
That first one you have selected (3,-3) works in both equations so it's correct.
good job.

you can do this guess and test method with multiple choice answers. If it works in both equations it is the solution. Otherwise use substitution or elimination to combine the two into one equation in only one variable. Then you can solve for the one variable first and use it to solve for the other.

3 0
2 years ago
a concave lens creates a virtual image at -47.0 cm and a magnification of +1.75. what is the focal length?
Lilit [14]

The focal length of given concave lens will be -26.85 cm

The height of an image to the height of an object is the ratio that is used to determine a lens' magnification. Additionally, it is provided in terms of object and image distance. It is equivalent to the object distance to image distance ratio.

Given  concave lens creates a virtual image at -47.0 cm and a magnification of +1.75.

We have to find focal length

The focal length can be found out by following way:

Magnification = m = +1.75

m = hi/h

hi = -47 cm

1.75 = -47/h

h = -26.85 cm

So the focal length of given concave lens will be -26.85 cm

Learn more about magnification factor here:

brainly.com/question/6947486

#SPJ10

8 0
1 year ago
What are the first three harmonics of a note produced on a 0.31 m long violin string if the waves on this string have a speed of
bezimeni [28]
Is that what you are looking for?
4 0
2 years ago
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