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Veseljchak [2.6K]
3 years ago
10

Consider the common measurement speed = 55 mph. What is the magnitude quantity?

Physics
1 answer:
noname [10]3 years ago
3 0

Answer:

Magnitude = 55

Quantity = Speed

Explanation:

We are told that the speed is 55 mph. This implies that the magnitude is 55 while the unit is mph.

Also, physical quantities are usually things that can be measured such as distance, voltage, temperature e.t.c

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Calculate the gravitational potential energy is a bicycle of mass 20kg and its rider of mass 50kg cycle to the top of a hill 120
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Explanation:

Gravitational Potential Energy can be calculated with the following formula:

mgh

Where m is mass, g is Gravitational Field Strength, and h is height. GFS on Earth is always 9.81, the combined mass of the cyclist and the bicycle is 70, and the height is 120. Multiplying these values together, we get:

82,404J.

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Answer:

A

Explanation:

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2 years ago
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Indicate whether each of the following statements is true or false. In a coal-fired power plant, chemical energy is first conver
denis23 [38]

Answer:

1. In a coal-fired power plant, chemical energy is first converted to thermal energy. TRUE.

The chemical energy in the coal is converted to thermal energy when the coal is burnt to produce steam.

2. In a coal-fired power plant, approximately 2/5 of original energy in the coal is lost to heat. FALSE.

Approximately 3/5 of the original energy is lost not 2/5 so this statement is false.

3. The molecules in cold air move faster than in hot air. FALSE.

Molecules with more heat move faster than molecules with less. Molecules in cold air therefore, will move slower than molecules in hot air.

6 0
3 years ago
parallel-plate capacitor is made of two square plates 25 cm on a side and 1.0 mmapart. The capacitor is connected to a 50.0-V ba
noname [10]

Answer:

6.9 x 10^-7 J  

3.5 x 10^-7 J

Explanation:

<u>Identify the unknown:  </u>

The energies stored in the capacitor before and after the plates are pulled farther apart  

<u>List the Knowns: </u>

Voltage of the battery: V = 50 V

Area of the plates: A = 0.25 x 0.25 = 0.0625 m^2

Original distance between the plates: d = 1 mm = 10^-3 m

New distance between the plates: d = 2 mm = 2 x 10^-3 m

Permittivity of free space: ∈o = 8.85 x 10^-12 C^2/Nm^2-

<u>Set Up the Problem:   </u>

Capacitance of a parallel-plate capacitor:  

C=∈o*A/d

Energy stored in a capacitor:  

U_c=(1/2)*V^2*C

<u>Solve the Problem:   </u>

<u>Before the plates are pulled farther apart:  </u>

C = 8.85 x 10^-12 x 0.0625/10^-3 = 5•53 x 10^-10 F  

U_c = (1/2) x (50)^2 x 5.53 x 10^-10= 6.9 x 10^-7 J  

<u>After the plates are pulled farther apart:  </u>

C = 8.85 x 10^-12 x 0.0625/2*10^-3 = 2•77 x 10^-10 F  

U_c = (1/2) x (50)^2 x 2•77 x 10^-10 = 3.5 x 10^-7 J  

The energy decrease because the capacitance decrease, so the stored charge decrease and transferred to the battery  

3 0
3 years ago
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