In a certain velocity selector consisting of perpendicular electric and magnetic fields, the charged particles move toward the e
ast, and the magnetic field is directed to the north. What direction should the electric field point?
1 answer:
Answer:
Down.
Explanation:
In the given question, the charged particle is moving towards the east direction. Suppose east direction towards the positive x-axis.
And the magnetic field directed towards to the north direction. Suppose north direction towards the positive y-axis.
Therefore force of magnetic field can be calculate by the formula,
Therefore force of the magnetic field is in positive z-axis means in an upward direction.
Now the force on the electric field must be in the opposite direction means it is in a downward direction.
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The speed of A and B immediately after collision is 5.28m/s
<u>Explanation:</u>
Mass of A is 6275kg
Speed of A is 6.5m/s
Mass of B is 5155kg
Speed of B is 3.8m/s
Track is frictionless.
A and B stick together.
speed of attached A and B = ?
mₐsₐ + mᵇsᵇ = (mₐ + mb) s
Therefore, The speed of A and B immediately after collision is 5.28m/s
Complete Question
The complete question is shown on the first uploaded image
Answer:
the compass direction of the resultant displacement is south of west
Explanation:
Generally using cosine we can obtain the resultant R as follows
=>
=>
We can obtain the direction of the resultant by first using sine rule to obtain angle C as follows
=>
=>
=>
Then the direction is obtained as
=>
=>
Hence the compass direction of the resultant displacement is south of west
