All categories

3 years ago

What is the number of Kelvins between the freezing point and the boiling point of water at a pressure of 1 atm?

Physics

1 answer:

Semmy [17]3 years ago

5 0

Answer:100 K

Explanation:

We know that Freezing Point of water is $0^{\circ}C$ at 1 atm

Converting it to Kelvin we get 273.15 K

Boiling Point of water is $100^{\circ}C$

converting it to Kelvin we get 373.15 K

Difference in the number we get =373.15-273.15=100 K

Temperature difference is independent of degree and will remain same for Celsius and Kelvin

You might be interested in

Physics Homework

katrin2010 [14]

Explanation:

a. Average speed = distance / time

= 100 m / 70 s

= 1.43 m/s

b. Average displacement = displacement / time

= 0 m / 70 s

= 0 m/s

Distance is the length of the path traveled. Displacement is the difference between the final position and initial position.

4 0

3 years ago

what features of stars are plotted on the Hertzsprung-Russell diagram? density and mass B. physical structure and composition ap

aliina [53]

Answer:

its luminosity (brightness) and temperature

Explanation:

3 0

2 years ago

Read 2 more answers

Mars completes one orbit around the Sun in approximately two Earth years. Mars orbits at an average distance to the Sun of about

satela [25.4K]

Answer:

about 0.8 times

Explanation: MARS is a planet named after a Roman God of War, it is the fourth planet from the sun and the Second smallest planet following Mercury.

The orbital Speed of a planet is the speed with which the planet uses to completely go round the Sun.

The orbital Speed of the Earth is 29.78kilmeters per Second.

The orbital Speed of Mar is 0.8*29.78kilometers per second/1

=23.824kilmeters per second.

3 0

3 years ago

A closed cylindrical tank of radius 3.5 m and height 2m is made from

Dahasolnce [82]

Explanation:

Total surface area of cylinder:

$2\pi \times r(h + r) \\ 2 \times \pi \times 3.5(3.5 + 2) \\ 2\pi \times 19.25 = 120.951317 \\ 120.95 \: {cm}^{2}$

sheet of metal required = 120.95 cm^2

3 0

2 years ago

Read 2 more answers

A 50.0 kg student climbs 5.00m up a rope at a constant speed. If the student's power output is 200.0 W, how long does it take th

hammer [34]

Answer:

The time taken by the student to climb is 12.25 seconds and work done is 2450 J.

Explanation:

Given that,

Mass of the student, m = 50 kg

The student climbs to a height of 5 meters at a constant speed.

The student's power output is 200.0 W, P = 200 W

The power of an object is given by work done divided by time taken. So,

$P=\dfrac{W}{t}$

(b) W is work done,

$W=mgh\\\\W=50\times 9.8\times 5\\\\W=2450\ J$

(b)

$t=\dfrac{W}{P}\\\\t=\dfrac{2450}{200}\\\\t=12.25\ s$

So, the time taken by the student to climb is 12.25 seconds and work done is 2450 J.

3 0

3 years ago