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2 years ago

What is the number of Kelvins between the freezing point and the boiling point of water at a pressure of 1 atm?

Physics

1 answer:

Semmy [17]2 years ago

5 0

Answer:100 K

Explanation:

We know that Freezing Point of water is $0^{\circ}C$ at 1 atm

Converting it to Kelvin we get 273.15 K

Boiling Point of water is $100^{\circ}C$

converting it to Kelvin we get 373.15 K

Difference in the number we get =373.15-273.15=100 K

Temperature difference is independent of degree and will remain same for Celsius and Kelvin

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A ball of mass 0.220 kg that is moving with a speed of 6.3 m/s collides head-on and elastically with another ball initially at r

Alex17521 [72]

Answer:

(a) Velocity of target is 2.7 m/s.

(b) Mass of target is 0.807 kg.

Explanation:

Mass of ball $m_{1}=0.22\;kg$

initial speed of the ball $v_{1i}=6.3\;m/s$

Final speed of the ball $v_{2f}=-3.6\;m/s$

Part (a) The second ball is initially at rest. So, by the conservation of momentum,

$p_{i}=p_{f}\\m_{1}v_{1i}+m_{2}v_{2i}=m_{1}v_{1f}+m_{2}v_{2f}\\0.22\times6.3+m_{2}\times 0=0.22\times(-3.6)+m_2v_{2f}\\m_2v_{2f}=2.178\:\:\:\:\;\;\;\;\;\;\;\;\;\; ...(1)$

Now, the velocity of approach is equal to the velocity of separation,

$v_{1i}-v_{2i}=v_{2f}-v_{1f}\\6.3-0=v_{2f}-(-3.6)\\v_{2f}=2.7\;m/s$

Part (b): From equation (1),

$m_2v_{2f}=2.178\\m_2=\frac{2.178}{2.7}\\m_2=0.806\;kg$

5 0

2 years ago

What frequency is received by a stationary mouse just before being dispatched by a hawk flying at it at 24.7 m/s and emitting a

Montano1993 [528]

Answer:

f' = 3665.51 Hz

Explanation:

given,

speed of the hawk = 24.7 m/s

frequency of screech emitted by the hawk = 3400 Hz

speed of sound = 331 m/s

By Doppler's effect

$f' = (\dfrac{v}{v-v_s}})f$

f' is the frequency received by the mouse

v is the speed of the sound

v_s is the speed of the hawk

now,

$f' = \dfrac{341}{341-24.7}}\times 3400$

f' = 1.078 x 3400

f' = 3665.51 Hz

The frequency received by the stationary mouse is equal to 3665.51 Hz

6 0

2 years ago

A submarine has a "crush depth" (that is, the depth at which

sergey [27]

Answer:

P =40.69 atm

Explanation:

We need to find the approximate pressure at a depth of 400 m.

It can be calculated as follows :

P = Patm + ρgh

Put all the values,

$P=1\ atm+1025 \times 9.81\times 400\times 9.8692\times 10^{-6}\ atm/Pa\\\\P=40.69\ atm$

So, the approximate pressure is equal to 40.69 atm.

3 0

2 years ago

Two objects of same material are travelling near you. Object A is a 1.1 kg mass traveling 10.2 m/s; object B is a 2 kg mass trav

Gnoma [55]

Answer:

Object A

Explanation:

The object that would make you feel worse if you're hit by it is the object possessing the highest momentum. Thus, we need to find the momentum of the two objects.

Momentum of an object is the product of its mass and that of it's velocity. Momentum is given by the formula

P = M * V, where

P = momentum

M = mass of the object

V = velocity of the object

Now, solving for object A, we have

P(a) = 1.1 * 10.2

P(a) = 11.22 kgm/s

And then, solving for object B, we have

P(b) = 2 * 5

P(b) = 10 kgm/s

The object when the highest momentum is object A, and thus would make you feel worse when hit by it

3 0

2 years ago

Which of the following is true about scientific models? (2 points) Select one: a. Models are used to simplify the study of thing

Vanyuwa [196]

Question: Which of the following is true about scientific models? Select one: A) Models are used to simplify the study of things. B) Computer models are the most reliable kind of model. C) Models explain past, present and future information. D) A model is accurate if it does not change over time.

Answer: A) Models are used to simplify the study of things.

Hope this helps!.

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~A.W~ZoomZoom44

5 0

3 years ago

Read 2 more answers