Answer is: intramolecular attractions are stronger.
Intramolecular attractions are the forces between atoms in molecule.
There are several types of intramolecular forces: covalent bonds, ionic bonds.
Intermolecular forces are the forces between molecules. The stronger are intermolecular forces, the higher is boiling point of compound, because more energy is needed to break interaction between molecules.
There are several types of intermolecular forces: hydrogen bonding, ion-induced dipole forces, ion-dipole forces andvan der Waals forces.
Hydrogen bonds are approximately 5% of the bond strength of covalent C-C or C-H bonds.
Hydrogen bonds strength in water is approximately 20 kJ/mol, strenght of carbon-carbon bond is approximately 350 kJ/mol and strengh of carbon-hydrogen bond is approximately 340 kJ/mol.
20 kJ/350 kJ = 0.057 = 5.7 %.
The reason for adding a limited amount and then an excess amount is that initially a metal hydroxide may form which becomes soluble when more base is added and the metal complex forms.
In qualitative analysis is a common to add the base in drops and then in excess. When added in drops, the metal hydroxide is formed. This metal hydroxide is often insoluble.
After this metal hydroxide is formed, the base could be added in excess such that the metal hydroxide dissolves in the excess base by forming a complex.
For instance;
CuCl2(aq) + 2NaOH(aq) -------> Cu(OH)2(s) + 2NaCl(aq)
Cu(OH)2(s) + 2OH^-(aq) -------> [Cu(OH)4]^2+(aq)
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Answer:
The answer to your question is: false.
Explanation:
Hydrogen bonding is tha attraction of hydrogen atoms to the oxygen or nitrogen of a different molecule not between the atoms of the same molecule.
So this description of hydrogen bonding is incorrect.
Answer:
The final pressure is 0.725 atm.
Explanation:
Gay Lussac's Law establishes the relationship between pressure and temperature of a gas when the volume is constant. This law says that when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, the pressure of the gas decreases. That is, pressure and temperature are directly proportional quantities.
Mathematically, Gay-Lussac's law states that, when a gas undergoes a constant volume transformation, the quotient of the pressure exerted by the gas temperature remains constant:
When analyzing an initial state 1 and a final state 2, the following is satisfied:
In this case:
- P1= 0.81 atm
- T1= 33 C= 306 K
- P2= ?
- T2= 1 C= 274 K
Replacing:
Solving:
P2= 0.725 atm
<u><em>The final pressure is 0.725 atm.</em></u>
