Answer:
8.59 rad/s
Explanation:
Given that:
A thin uniform cylindrical turntable radius = 2.7 m
with a mass (M) = 22 kg
initial angular speed (ω₁) = 12 rad/s
Mass of the clump of the clay (m) = 11 kg
Diameter (d) from the point of rotation = 1.7 m
We are to find the final angular velocity (ω₂) ,To do that; we apply the conservation of annular momentum; which is as follows:
L₁ = L₂
l₁ω₁ = l₂ω₂
( 0.5 × M × r²) × ω₁ = (0.5 × M × r² + md²) ω₂
Making ω₂ the subject of the formula ; we have:
Hence, the angular speed of the clay and turntable = 8.59 rad/s
Answer:
light scattering by particles in a colloid or in a very fine suspension
Let her initial velocity be U.
Let the width of the river be W.
She swims 3/5 the width of the river at U.
Remainder width = (1 - 3/5) = 2/5.
She then swims 2/5 the width with velocity U/2.
Average Speed = (Total Distance Traveled) / ( Total Time Taken).
Distance = Speed * time
time = Distance / Speed.
Time in first trip: = (3/5)W / U = 0.6W/U.
Time in second trip = (2/5)W / (U/2) = 0.4W / 0.5 U = 0.8W/U
Total Distance Traveled = W, width of the river.
Average Speed = W / (0.6W/U + 0.8W/U) = W / (1.4W/U)
= W * U / 1.4W
= U/1.4
= U * 10 / 14
= (5/7) U.
Therefore Average speed is (5/7) of the initial speed.
Answer:
Whats the question/word problem or where is the graph (if included) representing this problem?
Answer:
everything except smell,hate,love,cold
