Answer:
![\frac{L_1}{L_2} = \sqrt{(n^2 - 1)}](https://tex.z-dn.net/?f=%5Cfrac%7BL_1%7D%7BL_2%7D%20%3D%20%5Csqrt%7B%28n%5E2%20-%201%29%7D)
Explanation:
For this interesting problem, we use the definition of centripetal acceleration
a = v² / r
angular and linear velocity are related
v = w r
we substitute
a = w² r
the rectangular body rotates at an angular velocity w
We locate the points, unfortunately the diagram is not shown. In this case we have the axis of rotation in a corner, called O, in one of the adjacent corners we call it A and the opposite corner A
the distance OB = L₂
the distance AB = L₁
the sides of the rectangle
It is indicated that the acceleration in in A and B are related
we substitute the value of the acceleration
w² r_A = n r_B
the distance from the each corner is
r_B = L₂
r_A =
we substitute
\sqrt{L_1^2 + L_2^2} = n L₂
L₁² + L₂² = n² L₂²
L₁² = (n²-1) L₂²
Answer:
![E=8.13\times 10^{12}\ J](https://tex.z-dn.net/?f=E%3D8.13%5Ctimes%2010%5E%7B12%7D%5C%20J)
Explanation:
Given that,
The mass of a Hubble Space Telescope, ![m_1=1.16\times 10^4\ kg](https://tex.z-dn.net/?f=m_1%3D1.16%5Ctimes%2010%5E4%5C%20kg)
It orbits the Earth at an altitude of ![5.68\times 10^5\ m](https://tex.z-dn.net/?f=5.68%5Ctimes%2010%5E5%5C%20m)
We need to find the potential energy the telescope at this location. The formula for potential energy is given by :
![E=\dfrac{Gm_1m_e}{r}](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7BGm_1m_e%7D%7Br%7D)
Where
is the mass of Earth
Put all the values,
![E=\dfrac{6.67\times 10^{-11}\times 1.16\times 10^4\times 5.97\times 10^{24}}{5.68\times 10^5}\\\\E=8.13\times 10^{12}\ J](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7B6.67%5Ctimes%2010%5E%7B-11%7D%5Ctimes%201.16%5Ctimes%2010%5E4%5Ctimes%205.97%5Ctimes%2010%5E%7B24%7D%7D%7B5.68%5Ctimes%2010%5E5%7D%5C%5C%5C%5CE%3D8.13%5Ctimes%2010%5E%7B12%7D%5C%20J)
So, the potential energy of the telescope is
.
Answer;
C. The brightness of each bulb would remain the same even though the total resistance of the circuit would decrease.
Explanation;
-If light bulbs are connected in parallel to a voltage source, the brightness of the individual bulbs remains more-or-less constant as more and more bulbs are added to the circuit.
-The current increases as more bulbs are added to the circuit and the overall resistance decreases. In addition, if one bulb is removed from the circuit the other bulbs do not go out. Each bulb is independently linked to the voltage source
Choices 'C' and 'D' are both correct.
(Except in 'C', changing the temperature from 1°C to 3°C is not usually
described as 'cooling', and it's not the water's 'mass' that changes. But
water does contract in volume during that change.)