The sun <u><em>appears</em></u> brighter than any other star.
(It isn't really, but it looks that way because it's much much much much much much closer to us than any other star.)
A box is at rest on an inclined surface. The last diagram correctly illustrates all forces, including any component force, therefore the correct option is D.
<h3>Describe friction?</h3>
When two physical objects' surfaces come into contact, a force called friction acts to hinder or resist the relative motion of the items. Any two surfaces of things cannot simply slide over or across one another due to the friction force. It depends on the amount of force used on the object.
Additionally, there should be no net vertical forces acting on the inclined block. Fv=0
Therefore, the appropriate diagram is D.
Learn more about force on:
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A box is at rest on an inclined surface. Which diagram correctly illustrates all forces, including any component forces?
Assume the x-axis is parallel to the surface.
Answer:
D_momentum = 3.23[kg*m/s]
Explanation:
The change of moment can be easily determined by applying the principle of momentum and amount of movement
initial data are:
![m_{1}=0.17[kg]\\ m_{2}=0.17[kg]\\v_{1}=54[m/s]\\v_{2}=35[m/s]\\D_{momentum}= m_{1}*v_{1}-m_{2}*v_{2}\\D_{momentum}=0.17(54-35)\\D_{momentum}= 3.23[kg*m/s]](https://tex.z-dn.net/?f=m_%7B1%7D%3D0.17%5Bkg%5D%5C%5C%20m_%7B2%7D%3D0.17%5Bkg%5D%5C%5Cv_%7B1%7D%3D54%5Bm%2Fs%5D%5C%5Cv_%7B2%7D%3D35%5Bm%2Fs%5D%5C%5CD_%7Bmomentum%7D%3D%20m_%7B1%7D%2Av_%7B1%7D-m_%7B2%7D%2Av_%7B2%7D%5C%5CD_%7Bmomentum%7D%3D0.17%2854-35%29%5C%5CD_%7Bmomentum%7D%3D%203.23%5Bkg%2Am%2Fs%5D)
explorer 1 .........................
Given that,
Time period of simple pendulum is 1.55 s.
Time period of simple pendulum for A student =1.25 s
Time period of simple pendulum for B student =1.5 s
We know that
The accuracy is defined as how close a measurement is to a known value .
The result of student of A is 1.25 s. It is more precise because it has more significant figure than student B's result of 1.6 s.
But the measurement made by student B's is much closer the known value of 1.55 s.
Hence, The most probable source of error is the result of student A.