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love history [14]

3 years ago

15

The ability to make things happen is also called _____.

1 answer:

DerKrebs [107]3 years ago

3 0

Force bc it says the ability to make stuff happen

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What is each end of magnet A called?

leonid [27]

Answer: The ends of a magnet are called the poles. Each magnet has a north pole and south pole.

$\textit{\textbf{Spymore}}$

4 0

3 years ago

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A car has the velocity of 2.35 after 4.67 it's velocity is 9.89 what is the average acceleration

kiruha [24]

Average acceleration = (change in speed) / (time for the change) .

Change in speed = (ending speed) - (beginning speed)

=  (9.89 miles/hour) - (2.35 yards/second) = 26,839.2 ft/hr

Acceleration = (26,839.2 ft/hr) / (4.67 days) = 2,873.58 inch/hour²

6 0

3 years ago

The heating element of an iron operates at 110 V with a current of 9A. (a) What is the resistance of the iron?

Dmitrij [34]

Answer:

(A) 12.222 ohm (B) 990 W

Explanation:

We have given the voltage of the heating element V = 110 V

The current in the heating element i = 9 A

(a) According to ohm's law V =iR

So $110=9\times R$

$R=\frac{110}{9}=12.222ohm$

(b) The power dissipated in the resistor is given by $P=i^2R=9^2\times 12.222=990W$

So the power dissipated = 990 W

3 0

3 years ago

Consult Multiple-Concept Example 5 for insight into solving this problem. A skier slides horizontally along the snow for a dista

Gennadij [26K]

Answer:

The speed with which the skier was going is approximately 2.9906 m/s

Explanation:

The given parameters are;

The distance the skier slides before coming to rest, s = 12.4 m

The coefficient of friction between the skier and the snow, $\mu _k$ = 0.0368

Therefore, for conservation of energy, we have;

Initial kinetic energy = Work done by the kinetic friction force

Initial kinetic energy = 1/2·m·v²

The work done by the kinetic friction force = $\mu _k$ ×m×g×s

Where;

m = The mass of the skier

v = The speed with which the skier was going

g = The acceleration due to gravity = 9.8 m/s²

s = The distance the skier slides before coming to rest = 12.4 m

$\mu _k$ = The kinematic friction = 0.0368

Therefore, for conservation of energy, we have;

1/2·m·v² = $\mu _k$ ×m×g×s

1/2·v² = $\mu _k$ ×g×s

v² = 2× $\mu _k$ ×g×s = 2 × 0.0368 × 9.8 × 12.4 = 8.943872

v = √(8.943872) ≈ 2.99063070271 ≈ 2.9906 m/s

The speed with which the skier was going = v ≈ 2.9906 m/s.

3 0

3 years ago

A 900 N crate is being pulled across a level floor by a force F of 340 N at an angle of 23° above the horizontal. The coefficien

Olegator [25]

Answer:

0.958891203 m/s²

Explanation:

N = Weight of crate = 900 N

$\mu$ = Coefficient of friction = 0.25

Force of friction acting on the force applied

$f=\mu N\\\Rightarrow f=0.25\times 900\\\Rightarrow f=225\ N$

Force used to pull the crate

$F=340cos 23\\\Rightarrow F=312.97165\ N$

The net force is

$F_n=F-f\\\Rightarrow F_n=312.97167-225\\\Rightarrow F_n=87.97167\ N$

Acceleration is given by

$a=\frac{F_n}{m}\\\Rightarrow a=\dfrac{87.97167}{\dfrac{900}{9.81}}\\\Rightarrow a=0.958891203\ m/s^2$

The magnitude of the acceleration of the crate is 0.958891203 m/s²

4 0

4 years ago