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kenny6666 [7]
2 years ago
15

Answer quick and correctly for brainliest (remind me to give brainliest i usually forget.) PLEASE ANSWER ITS MY LAST QUESTION AN

D IM ABSELOUTELY CLUELESS
Marine plants, such as algae, use CO2 to make energy. Ocean fertilization is the introduction into oceans of nutrients that encourage the growth of these plants. How can this technique affect the pH in oceans that already have higher than normal CO2 readings?
Physics
2 answers:
Kipish [7]2 years ago
4 0

Answer:

It can already have a higher than normal co2 or pH reading because off all the things that get put in the ocean.

Explanation:

I got it correct

iris [78.8K]2 years ago
3 0

Answer:

Explanation:

Geoengineering schemes involving ocean fertilization to affect climate have a low chance of success, according to the first summary for policymakers on the issue.

Failure to tackle rising greenhouse gas emissions effectively has led to intensifying debate on geoengineering – deliberate large-scale schemes to slow the rate at which Earth is heating up. The public debate often mixes opinion with fact so scientists have now released the first summary for policymakers on ocean fertilization, one of the earliest geoengineering proposals. The authors report that the chances of success of using ocean fertilization to deal with climate change is low.

Ocean fertilization involves adding iron or other nutrients to the surface of the ocean to trigger growth of microscopic marine plants.  These plants use dissolved carbon dioxide to grow, which led to the idea that deliberate fertilization of the ocean on a large scale would remove carbon dioxide from the atmosphere.

Lead author of the report Professor Doug Wallace from the Leibniz-Institut für Meereswissenschaften (IFM-GEOMAR) says: “The published findings suggest that even very large-scale fertilization would remove only modest amounts of carbon dioxide from the atmosphere over 100 years”.

For two decades, marine scientists have been carrying out a series of small-scale fertilization experiments to understand how ocean ecosystems respond to environmental change. However the experiments were not designed to address issues relating to geoengineering. Proposals to scale up this approach to slow climate warming or be included within emissions trading schemes to generate carbon credits have stimulated intense debate and criticism amongst scientists and the public.

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A hollow sphere of inner radius 8.82 cm and outer radius 9.91 cm floats half-submerged in a liquid of density 948.00 kg/m^3. (a)
kari74 [83]

Answer:

a) 0.568 kg

b) 474 kg/m³

Explanation:

Given:

Inner radius = 8.82 cm = 0.0882 m

Outer radius = 9.91 cm = 0.0991 m

Density of the liquid = 948.00 Kg/m³

a) The volume of the sphere = \frac{4\pi}{3}\times(0.0991^2-0.0882^2)

or

volume of sphere = 0.0012 m³

also, volume of half sphere = \frac{\textup{Total volume}}{\textup{2}}

or

volume of half sphere = \frac{\textup{0.0012}}{\textup{2}}

or

Volume of half sphere =0.0006 m³

Now, from the Archimedes principle

Mass of the sphere = Weight of the volume of object submerged

or

Mass of the sphere = 0.0006× 948.00 = 0.568 kg

b) Now, density =  \frac{\textup{Mass}}{\textup{Volume}}

or

Density = \frac{\textup{0.568}}{\textup{0.0012}}

or

Density = 474 kg/m³

8 0
3 years ago
1. What are the units of : pressure, force , area
White raven [17]

Pressure- Pascal(N/m^2)

Force- Newton

Area-m^2(Square metre)

<u>Explanation:</u>

  • Pressure is force continuous force applied to an object. The applied force is always perpendicular to the surface of the object.
  • Force is a push or pulls on an object by an external body where it changes its state from rest to motion.
  • Force is said to have both magnitude and direction.
  • Area is the portion that shows the scale of a 2D form or configuration in the level. The covering area is its analog on the 2D surface of a 3D object.
6 0
3 years ago
What is the average power output pf a weight lifter who can lift 250 kg 2.0 m in 2.0 s
liq [111]

Answer:

Power = 2.45Kw or 2450 Watts.

Explanation:

<u>Given the following data;</u>

Mass, m = 250kg

Height, h = 2m

Time, t = 2secs

We know that acceleration due to gravity, g is equal to 9.8m/s²

Power can be defined as the energy required to do work per unit time.

Mathematically, it is given by the formula;

Power = \frac {Energy}{time}

But Energy = mgh

Substituting into the equation, we have

Power = \frac {mgh}{time}

Power = \frac {250*9.8*2}{2}

Power = \frac {4900}{2}

Power = 2450 Watts

To convert to kilowatt (Kw), we would divide by 1000

Power = 2450/1000

Power = 2.45Kw.

Therefore, the average power output of the weightlifter is 2.45 Kilowatts.

8 0
3 years ago
2. physical quantities which do not depend on any physical quantities for their measurements are known as​
seropon [69]

Answer:

Fundamental quantities

5 0
2 years ago
A car travels 82 meters do North and 14 seconds the car turns around and travels 44 m due south in four seconds what is the magn
Yakvenalex [24]

Answer:

2.11 m/s

Explanation:

Take north to be positive and south to be negative.

Average velocity = displacement / time

v = (82 m + -44 m) / (14 s + 4 s)

v = 2.11 m/s

The velocity is positive, so it is 2.11 m/s north.  The magnitude of the velocity is 2.11 m/s.

8 0
3 years ago
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