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kenny6666 [7]
2 years ago
15

Answer quick and correctly for brainliest (remind me to give brainliest i usually forget.) PLEASE ANSWER ITS MY LAST QUESTION AN

D IM ABSELOUTELY CLUELESS
Marine plants, such as algae, use CO2 to make energy. Ocean fertilization is the introduction into oceans of nutrients that encourage the growth of these plants. How can this technique affect the pH in oceans that already have higher than normal CO2 readings?
Physics
2 answers:
Kipish [7]2 years ago
4 0

Answer:

It can already have a higher than normal co2 or pH reading because off all the things that get put in the ocean.

Explanation:

I got it correct

iris [78.8K]2 years ago
3 0

Answer:

Explanation:

Geoengineering schemes involving ocean fertilization to affect climate have a low chance of success, according to the first summary for policymakers on the issue.

Failure to tackle rising greenhouse gas emissions effectively has led to intensifying debate on geoengineering – deliberate large-scale schemes to slow the rate at which Earth is heating up. The public debate often mixes opinion with fact so scientists have now released the first summary for policymakers on ocean fertilization, one of the earliest geoengineering proposals. The authors report that the chances of success of using ocean fertilization to deal with climate change is low.

Ocean fertilization involves adding iron or other nutrients to the surface of the ocean to trigger growth of microscopic marine plants.  These plants use dissolved carbon dioxide to grow, which led to the idea that deliberate fertilization of the ocean on a large scale would remove carbon dioxide from the atmosphere.

Lead author of the report Professor Doug Wallace from the Leibniz-Institut für Meereswissenschaften (IFM-GEOMAR) says: “The published findings suggest that even very large-scale fertilization would remove only modest amounts of carbon dioxide from the atmosphere over 100 years”.

For two decades, marine scientists have been carrying out a series of small-scale fertilization experiments to understand how ocean ecosystems respond to environmental change. However the experiments were not designed to address issues relating to geoengineering. Proposals to scale up this approach to slow climate warming or be included within emissions trading schemes to generate carbon credits have stimulated intense debate and criticism amongst scientists and the public.

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When you rub a plastic rod with fur, the plastic rod becomes negatively charged and the fur becomes positively charged. As a con
Yuri [45]

Answer: C. the rod gains mass and the fur loses mass.

Explanation:Atomic particles have mass. The electron has a mass that is approximately 1/1836 that of the proton and with exchange exchange of charge this is also factored in. The movement of effect described above is known as the triboelectic charging process—charging by friction—which results in a transfer of electrons between the two objects when they are rubbed together. Plastic having a much greater affinity for electrons than animal fur pulls electrons from the atoms of fur, leaving both objects with an imbalance of charge. The plastic rod would have an excess of electrons and the fur has a shortage of electrons. Having an excess of electrons, the plastic is charged negatively and has more mass. In the same vein, the shortage of electrons on the fur leaves it with a positive charge and consequently with lesser mass.

4 0
3 years ago
Is a caterpillar turning into a butterfly is or is not a metamorphosis
alukav5142 [94]
It kinda makes sense that it would be considered a metamorphosis.
4 0
3 years ago
Read 2 more answers
Wavelength is measured in hertz true or false?
g100num [7]
Wavelength is measured in various units of distance (mm, cm, m, etc.). Frequency uses hertz, but that is not what the question is asking. Therefore, the answer is false.
3 0
2 years ago
A plane travels at a speed of 205mph in still air. Flying with a tailwind, the plane is clocked over a distance of 1000 miles. F
vaieri [72.5K]

While plane is moving under tailwind condition it took time "t"

so here we will have

t = \frac{d}{v_{net}}

here net speed of the plane will be given as

v_{net} = v + v_w

t = \frac{1000}{205 + v_w}

similarly when it moves under the condition of headwind its net speed is given as

v_{net} = v - v_w

now time taken to cover the distance is 2 hours more

t + 2 = \frac{1000}{205 - v_w}

now solving two equations

\frac{1000}{205 + v_w} + 2 = \frac{1000}{205 - v_w}

solving above for v_w we got

v_w = 40.4 mph

6 0
3 years ago
Answer either one or both questions! Must explain and show work to receive brainliest!
MariettaO [177]
<span>F x L = W x X whereW=weight is total load = 80, L is length from fulcrum which is the unknown and what we are solving for. x= length we know. and F equals 50 force we know. So (W*X)/F=LL equals 64</span>
3 0
3 years ago
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