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Lerok [7]
3 years ago
12

A friend is making vegetable soup. he add some salt to the simmering broth. the salt dissolves, and your friend says the broth s

altiness it’s just right. after two more hours of cooking on the stove top the broth is way too salty, what happened?
Physics
1 answer:
noname [10]3 years ago
7 0

Answer:

It is due to the effect of temperature on our taste receptors.

Explanation:

  • The taste receptors on our tongue is extremely sensitive.
  • It can vary the taste of same element due to difference in temperature. So cooking further, the temperature of that food is increased which makes it taste more saltier than before.
  • The solubility may also have the effect on this case because solubility increases with the increase in temperature. So at high temperature salt may expand and dissolve more to make the food saltier than before.
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Suppose two vectors have unequal magnitudes. can their sum be zero? explain
GalinKa [24]

Answer;

-  No, Two vectors of unequal magnitude can never sum to zero.

Explanation;

-Two vectors of equal magnitude that are pointing in opposite directions will sum to zero.

-Two vectors of unequal magnitude can never sum to zero. If they point along the same line, since their magnitudes are different, the sum will not be zero.

- If they point in different directions, then you can always decompose one vector into two components: one along the other vector and one perpendicular to the other vector. In this case, the perpendicular component can never be eliminated.

5 0
3 years ago
In a simple harmonic motion, when the displacement from the equilibrium position is at its maximum,
Keith_Richards [23]

Answer:

option B

Explanation:

The correct answer is option B

When the displacement in the harmonic motion is maximum then kinetic energy at the maximum point is minimum and the potential energy is maximum at that point.  

So, when the displacement is maximum, spring force magnitude is also maximum because the force is proportional to the displacement and also the magnitude of the acceleration is maximum so, the net force is also maximum.

7 0
2 years ago
Arrange these source charges in order from least to greatest magnitude.
Anestetic [448]
C ,A ,B ,D

I think I’m to sure
5 0
3 years ago
Read 2 more answers
An object with a 25 µC charge is 0.54 m away from a second charged object. They experience a force of 3250 N. What is the charge
nekit [7.7K]
25 uc charge is 0.54 m away
6 0
2 years ago
(4A) The mass of Earth is 5.972 * 10^24 kg, and the radius of Earth is 6,371 km.
faltersainse [42]

Answer:

x₁ = 345100 km

Explanation:

The direction of the attraction forces between the earth and the object, and between the moon and the object, are in opposite direction and  (along the straight line between the centers of earth and moon) and as gravity is always attractive, the net force will become zero when both forces are equal. According to this:

Let  call "x₁"  distance between center of the earth and the object, and

"x₂" the distance between center of the moon and the object, Mt mass of the earth, Ml mass of the moon, m₀ mass of the object

we can express:

F₁  ( force between earth and the object )

F₁ = K *  Mt * m₀/ ( x₁)²        K is a gravitational constant

F₂  (force between mn and the object)

F₂ = K * Ml * m₀ / (x₂)²

Then:

F₁ = F₂               K*Mt*m₀ / x₁²   =  K*Ml*m₀ /x₂²

Or  simplifying the expression

Mt/ x₁²  =  Ml/ x₂²

We know that   x₁   +  x₂  = 384000 Km then

x₁ =  384000 - x₂

Mt/( 384000 - x₂)²  =  Ml / x₂²

Mt *  x₂²  =  Ml *( 384000 - x₂)²

We need to solve for x₂

Mt *  x₂²  =  Ml *[ ( 384000)² + x₂² - 768000*x₂]

By substitution:

5.972*10∧24*x₂² = 7.348*10∧22 * [ 1.47*10∧11 ] + 7.348*10∧22*x₂² -

                                7.348*10∧22*768000*x₂

Simplifying by 10∧22

5.972*10²*x₂²  = 7.348* [ 1.47*10∧11 ] + 7.348*x₂²- 7.348*768000*x₂

Sorting out

5.972*10²*x₂²- 7.348*x₂² = 10.80*10∧11 - 56,43* 10∧5*x₂

(597,2 - 7,348 )* x₂²  = 10.80*10∧11 - 56.43*10∧5*x₂

590x₂²  + 56.43*10∧5*x₂ - 10.80*10∧11 = 0

Is a second degree equation

x₂  =  -56.43*10∧5 ± √3184*10∧10 + 25488*10∧11  / 1160

x₂ ₁  = -56.43*10∧5 + √3184*10∧10 + 25488*10∧11  / 1160

x₂ ₁  =  -56.43*10∧5 + √3184*10∧10 + 254880*10∧10  / 1160

x₂ ₁  = -56.43*10∧5 + 10∧5 [ √3184 + 254880 ] /1160

x₂ ₁  =  -56.43*10∧5 + 508* 10∧5  / 1160

x₂ ₁  =  451.27*10∧5/1160

x₂ ₁  =  4512.7*10∧4 /1160

x₂ ₁  = 3.89*10∧4  km (distance between the moon  and the object)

x₂ ₁  = 38900 km

x₂ = 38900 km

We dismiss the other solution because is negative and there is not a negative distance

Then the distance between the earth and the object is:

x₁  = 384000 - x₂

x₁ = 384000 - 38900

x₁ = 345100 km

5 0
3 years ago
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