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3 years ago

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A friend is making vegetable soup. he add some salt to the simmering broth. the salt dissolves, and your friend says the broth s

altiness it’s just right. after two more hours of cooking on the stove top the broth is way too salty, what happened?

1 answer:

noname [10]3 years ago

7 0

Answer:

It is due to the effect of temperature on our taste receptors.

Explanation:

The taste receptors on our tongue is extremely sensitive.
It can vary the taste of same element due to difference in temperature. So cooking further, the temperature of that food is increased which makes it taste more saltier than before.
The solubility may also have the effect on this case because solubility increases with the increase in temperature. So at high temperature salt may expand and dissolve more to make the food saltier than before.

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Answer:

The angle of separation is $\Delta \theta = 0.93 ^o$

Explanation:

From the question we are told that

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The refractive index of red light in diamond is $n_r = 2.41$

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Where $\theta_r$ is the angle of refraction

=> $sin \theta_r = \frac{sin \theta_i}{n}$

Now considering violet light

$sin \theta_r__{v}} = \frac{sin \theta_i}{n_v}$

substituting values

$sin \theta_r__{v}} = \frac{sin (56)}{2.46}$

$sin \theta_r__{v}} = 0.337$

$\theta_r__{v}} = sin ^{-1} (0.337)$

$\theta_r__{v}} = 19.69^o$

Now considering red light

$sin \theta_r__{R}} = \frac{sin \theta_i}{n_r}$

substituting values

$sin \theta_r__{R}} = \frac{sin (56)}{2.41}$

$sin \theta_r__{R}} = 0.344$

$\theta_r__{R}} = sin ^{-1} (0.344)$

$\theta_r__{R}} = 20.12^o$

The angle of separation between the red light and the violet light is mathematically evaluated as

$\Delta \theta = \theta_r__{R}} - \theta_r__{V}}$

substituting values

$\Delta \theta =20.12 - 19.69$

$\Delta \theta = 0.93 ^o$

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