Question

Air in a closed cylinder is heated from 25 degree to 36 degree. If the initial pressure is 3.80 atm what is the final pressure ?

Answer 1

Aww man, I love these types of problems!!!
So, it's a simple formula:
P1*V1/T1=P2*V2/T2

In this case, we remove V(volume) as there is none listed, leaving this:
P1/T1=P2=T2

Think you got it from here? All you gotta do is plug in the numbers and solve
If you have any further problems, just let me know!!

Answer 2

Answer:

5.47 atm

Explanation:

We have an initial state in which the air is at a temperature of 25 degrees and a pressure of 3.80 atm

We also have a final state in which the temperature is 36 degrees and we have to find out the pressure

For two different states it meets the following equation

$\frac{P_1.V_1}{T_1}=\frac{P_2.V_2}{T_2}$

As we are told that the air is in a closed cylinder the volume is always constant, it is the same on both sides ($V_1=V_2$) so we can simplify it and the equation is as follows

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

Now we clear the final pressure ($P_2$)

$\frac{P_1}{T_1}.T_2=P_2\\\\\frac{3.80atm}{25\ºC}.36\ºC=P_2\\\\5.47 atm= P_2$

The final pressure is 5.47 atm