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3 years ago

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In the problem 62x45,what are the partial products

1 answer:

Gnom [1K]3 years ago

8 0

In the problem 62x45, what are the partial products? To acquire the possible partial products we can just multiply the two numbers to produce the possible numbers at hand. <span><span>
1. </span>62 x 45 = 2790</span> <span><span>
2. </span>45 x 62 = 2790</span>

Same outcome which is explained by the comutative property of multiplication.

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Using the formula F=9/5C+32, find C when F= 75.

den301095 [7]

Answer:

DIVIDING 9 AND 5 = 23.8

9/5 FRACTION = 0.04

Step-by-step explanation:

If 9/5 means 9 divided by 5

FLIP THE EQUATION

9/5C + 32 = 75

9/5C + 32 - 32 = 75 -32

9/5C = 43

9/5 = 1.8

1.8C = 43

1.8C/1.8 = 4

If 9/5 means 9/5ths fraction

FLIP THE EQUATION

9/5C + 32 = 75

9/5C + 32 - 32 = 75 -32

9/5C = 43

9/5C / 9/5 = 43 / 9/5

C = 0.04

Hope this helps i thought 9/5 was 9 divide by 5. If it was 9/5 as a fraction i also made that equation too.

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3 years ago

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If the probability that a randomly chosen college student uses a ride sharing app is 0.27, then what is the probability that a r

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2 years ago

Find all solutions of the given system of equations (If the system is infinite many solution, express your answer in terms of x)

lisov135 [29]

Answer:

(a) The system of the equations $\left \{ {2x-3y\:=3} \atop {4x-6y\:=3}} \right.$ has no solution.

(b) The system of the equations $\left \{ {4x-6y\:=10} \atop {16x-24y\:=40}} \right.$ has many solutions $y=\frac{2x}{3}-\frac{5}{3}$

Step-by-step explanation:

(a) To find the solutions of the following system of equations $\left \{ {2x-3y\:=3} \atop {4x-6y\:=3}} \right.$ you must:

Multiply $2x-3y=3$ by 2:

$\begin{bmatrix}4x-6y=6\\ 4x-6y=3\end{bmatrix}$

Subtract the equations

$4x-6y=3\\-\\4x-6y=6\\------\\0=-3$

0 = -3 is false, therefore the system of the equations has no solution.

(b) To find the solutions of the system $\left \{ {4x-6y\:=10} \atop {16x-24y\:=40}} \right.$ you must:

Isolate x for $4x-6y=10$

$x=\frac{5+3y}{2}$

Substitute $x=\frac{5+3y}{2}$ into the second equation

$16\cdot \frac{5+3y}{2}-24y=40\\8\left(3y+5\right)-24y=40\\24y+40-24y=40\\40=40$

The system has many solutions.

Isolate y for $4x-6y=10$

$y=\frac{2x}{3}-\frac{5}{3}$

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3 years ago

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