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ASHA 777 [7]
4 years ago
7

Arrange the events of the earliest stellar formation in sequential order.

Physics
1 answer:
Katyanochek1 [597]4 years ago
7 0

Answer:

Arranging the events of the earliest stellar formation in sequential order, we get - 3. The big bang occurs. --> 2. Pockets of elements in higher concentrations begin experiencing greater gravitational force.  --> 1. Hydrogen atoms shed their electrons and fuse together to form larger helium atoms.  --> 4. Hydrogen and helium disperse into the universe in uneven concentrations.  --> 6. The gas clouds begin reducing in volume, which leads to increases in density, pressure, and temperature. --> 5. The temperature of gas clouds surpasses 14 million Kelvin.

Correct Order : Option 3, 2, 1, 4, 6, 5  

Explanation:

The evolution in Stellar is the process of evolution through which a star which the stellar body changes its morphology over the course of time. All stars being the stellar body are created from collapsing clouds of gas and dust. These collapsing cloud of gas and dust are called nebulae or molecular clouds.

The collapse occurs with gravitational collapse of cool, dense molecular clouds. When the cloud collapses, fragments are formed of smaller regions. These fragments then contract to form stellar cores.

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a stone is thrown horizonttaly from a cliff of a hill with an initial velocity of 30m/s it hits the ground at a horizontal dista
ELEN [110]

Answer:

a) Time = 2.67 s

b) Height = 35.0 m

Explanation:

a) The time of flight can be found using the following equation:

x_{f} = x_{0} + v_{0_{x}}t + \frac{1}{2}at^{2}   (1)

Where:

x_{f}: is the final position in the horizontal direction = 80 m

x_{0}: is the initial position in the horizontal direction = 0

v_{0_{x}}: is the initial velocity in the horizontal direction = 30 m/s

a: is the acceleration in the horizontal direction = 0 (the stone is only accelerated by gravity)

t: is the time =?  

By entering the above values into equation (1) and solving for "t", we can find the time of flight of the stone:  

t = \frac{x_{f}}{v_{0}} = \frac{80 m}{30 m/s} = 2.67 s

b) The height of the hill is given by:

y_{f} = y_{0} + v_{0_{y}}t - \frac{1}{2}gt^{2}

Where:

y_{f}: is the final position in the vertical direction = 0

y_{0}: is the initial position in the vertical direction =?

v_{0_{y}}: is the initial velocity in the vertical direction =0 (the stone is thrown horizontally)            

g: is the acceleration due to gravity = 9.81 m/s²

Hence, the height of the hill is:

y_{0} = \frac{1}{2}gt^{2} = \frac{1}{2}9.81 m/s^{2}*(2.67 s)^{2} = 35.0 m  

I hope it helps you!

5 0
3 years ago
These has two questions, any help would be much appreciated. Ignore the current answers.
Sati [7]
Bro sorry I don’t know these answer but keeep trying
4 0
3 years ago
How often do very active sunspot and solar flare cycles take place?
alexira [117]
11 Years

Usually sunspot and solar flare cycles vary. But the average duration occurs every 11 years, sometimes 9-14 years as well.
3 0
3 years ago
Read 2 more answers
What is the potential energy of a 3 kilogram-ball that is on the ground?
Aleks [24]
The answer is 0
potential energy= mass• gravity (9.8m/s)• height.
Your mass 3kg. I believe your need to convert this to grams (3000g) and then multiply by 9.8. Since your height is 0 because the ball is on the ground then your potential energy is 0
3 0
3 years ago
Read 2 more answers
Power of sunlight on Earth The Sun emits about 3.9 * 1026 J of electromagnetic radiation each second. (a) Estimate the power tha
ratelena [41]

Answer:

a)6.34 x  10^{7}W/m²

b)1.37 x 10^{3 W/m²

c) see explanation.

Explanation:

a)The relation of intensity'I' of the radiation and area 'A' is given by:

I= P/A

where P= power of sunlight i.e 3.9 x 10^{26} J

and the area of the sun is given by,

A= 4πR_{sun} => 4π(\frac{1.4*10^{9} }{2} )^{2}

A=6.15 x 10^{18}m²

I_{sun} =  3.9 x 10^{26} / 6.15 x 10^{18} =><u> 6.34 x  </u>10^{7}<u>W/m²</u>

b) First determine the are of the sphere in order to determine intensity at the surface of the virtual space

A= 4πR

Now R= 1.5 x 10^{11m

A=  4π x 1.5 x 10^{11 =>2.83 x 10^{23 m²

The power that each square meter of Earths surface receives

I_{earth =   3.9 x 10^{26}/2.83 x 10^{23 =><u>1.37 x </u>10^{3<u> W/m²</u>

<u />

c) in part (b), by assuming the shape of the wavefront of the light emitted by the Sun is a spherical shape so each point has the same distance from the source i.e sun on the wavefront.

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3 years ago
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