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Bumek [7]
2 years ago
11

What process primes a molecule to change in a way that increases its activity, produces motion, or does work

Physics
1 answer:
kirza4 [7]2 years ago
4 0

Answer:

cellular respiration.

explanation: cellular respiration, the process by which organisms combine oxygen with foodstuff molecules, diverting the chemical energy in these substances into life-sustaining activities and discarding, as waste products, carbon dioxide and water.

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mezya [45]

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46 dgres is the answer

Explanation:

<em>plz</em><em> </em><em>mark</em><em> </em><em>me</em><em> brainliest</em><em> plz</em><em> Plz</em>

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2 years ago
How long can you keep open beer in the fridge?
Gre4nikov [31]
You can keep it for as long as you want; you're the boss of your fridge. 
But anyway, an open beer bottle can stay good in the fridge for up to 96 hours, probably more. 
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2 years ago
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If hot air rises then why is it cold in space please explain in detail thank you
Helen [10]
Hot air has a lower density than the surrounding atmosphere, therefore,it will rise.. The reason it is "cold" in the upper atmosphere is actually because of a lower air density.
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3 years ago
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Calcium has a charge of +2. The chart lists the charges of different ions.
dexar [7]
The possible resulting chemical formulas for an ionic compound with calcium given the respective charges of the ions are: CaO, CaMg, or CaF₂ and CaO, CaF₂, or CaCl₂. This is because when dealing with these compounds, you simply need to interchange the oxidation state of the two elements and place as the subscript of the element. For instance, when we have Ca²⁺ and F⁻, the result is CaF₂. However, when the oxidation states of the two compounds are equal, the subscript is 1. That is, for Ca²⁺ and Mg²⁻, the result is CaMg. And for Ca²⁺ and Cl⁻, the result is CaCl₂. 
3 0
3 years ago
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A river flows with a uniform velocity vr. A person in a motorboat travels 1.22 km upstream, at which time she passes a log float
storchak [24]

Answer:

 t ’= \frac{1450}{0.6499 + 2 v_r},  v_r = 1 m/s       t ’= 547.19 s

Explanation:

This is a relative velocity exercise in a dimesion, since the river and the boat are going in the same direction.

By the time the boat goes up the river

        v_b - v_r = d / t

By the time the boat goes down the river

        v_b + v_r = d '/ t'

let's subtract the equations

       2 v_r = d ’/ t’ - d / t

       d ’/ t’ = 2v_r + d / t

       t' = \frac{d'}{ \frac{d}{t}+ 2 v_r }

In the exercise they tell us

         d = 1.22 +1.45 = 2.67 km= 2.67 10³ m

         d ’= 1.45 km= 1.45 1.³ m

at time t = 69.1 min (60 s / 1min) = 4146 s

the speed of river is v_r

      t ’= \frac{1.45 \ 10^3}{ \frac{ 2670}{4146} \  + 2 \ v_r}

      t ’= \frac{1450}{0.6499 + 2 v_r}

In order to complete the calculation, we must assume a river speed

          v_r = 1 m / s

       

let's calculate

      t ’= \frac{ 1450}{ 0.6499 + 2 \ 1}

      t ’= 547.19 s

8 0
3 years ago
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