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Sav [38]
3 years ago
9

Which of the following plays a major role in creating surface currents?

Physics
2 answers:
kap26 [50]3 years ago
6 0
I'm pretty sure it is A but I would still check with someone :)
maksim [4K]3 years ago
4 0

The answer is B: Wind patterns. Hope this helps :)

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What pressure, in millimeters of mercury (mm Hg), is equivalent to 2.13 atmospheres
Sati [7]
The "Standard Atmosphere" is 760 mm Hg . 2.13 times that pressure is (2.13 x 760) = 1,618.8 mm Hg.
6 0
3 years ago
A simple generator is used to generate a peak output voltage of 25.0 V . The square armature consists of windings that are 7.0 c
4vir4ik [10]

Answer:

<h3>The 28 loops wound on the square armature</h3>

Explanation:

Peak output voltage \epsilon _{peak}  = 25 V

Area of square armature A = (7 \times 10^{-2} )^{2}  = 49 \times 10^{-4}

Magnetic field B = 0.490 T

Angular frequency \omega = 2\pi f = 2 \pi \times 60 = 120\pi

According to the law of electromagnetic induction,

     \epsilon _{peak} = NBA \omega

Where N = number of loops of wire.

  N = \frac{25}{49 \times 10^{-4} \times 0.49 \times 120\pi  }

  N = 27.6 ≅ 28

Thus, 28 loops of wire should be wound on the square armature.

6 0
3 years ago
Please help me**** i need some answers now
sweet-ann [11.9K]
Output can not be greater than input because the conversion of energy can not be greater than 100%.
4 0
3 years ago
A 1.2 kg basketball is thrown upwards. What is the potential energy of the basketball at the top of its path if it reaches a hei
Dahasolnce [82]

Answer:

Answer is 183.6 J

Explanation:

Using the Physics reference sheet the formula for Potential energy is

(mass) x (gravity) x (height)

Mass= 1.2

Gravity I used is 9.81 (use 10 to get the answer most schools use)

Height= 15.6

5 0
3 years ago
A man on the Moon observes two spaceships coming toward him from opposite directions at speeds of 0.600c and 0.600c. What is the
vaieri [72.5K]

Answer:

If we use the equation for the transformation of velocities for moving frames:

v' = (v - u) / (1 - u * v / c^2) where we measure the speed of v' approaching from the left where v is in a frame moving at -u towards v'

v' = (.6 c - (-.6 c)) / (1 - (-.6 c) * .6 c / c^2) = 1.2 c / (1 + .6 * .6)

or v' = 1.2 c / (1 + .36) = .88 c

v is approaching from the left at .6 c in the reference frame and the other frame approaches from the right at -.6 c with speed u  (-.6 c) and we measure the speed of v as seen in the frame moving to the left

5 0
3 years ago
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