Answer:
The stuntman will not make it
Explanation:
At the bottom of the swing, the equation of the forces acting on the stuntman is:
where:
T is the tension in the rope (upward)
mg is the weight of the man (downward), where
m = 82.5 kg is his mass
is the acceleration due to gravity
is the centripetal force, where
v = 8.65 m/s is the speed of the man
r = 12.0 m is the radius of the circule (the length of the rope)
Solving for T, we find the tension in the rope:
Since the rope's breaking strength is 1000 N, the stuntman will not make it.
Answer:
18 cm
Explanation:
The picture attached below shows the full explanation. Thank you and i hope it helps
Answer:
The resulting velocity of the ball after it hits the racket was of V= 51.6 m/s
Explanation:
m= 55.6 g = 0.0556 kg
t= 2.8 ms = 2.8 * 10⁻³ s
F= 1290 N/ms * t - 330 N/ms² * t²
F= 1024.8 N
F*t= m * V
V= F*t/m
V= 51.6 m/s
You must apply Archimides' principle.
The barge will sink until the sum of the forces on it equals zero.
The two forces are the weight of the barge (with sand) and the buoyancy force, the force exerted by the liquid (fresh water) on the barge.
Then, weight of the barge with sand = m*g = 600 kg * g
Buoyancy force = density of the fluid * Volume of displaced fulid * g
Then, m*g = density of the fulid * Volume of displaced fluid * g
m*g = df * Vf * g
m = df*Vf => Vf = m/df = 600 kg / 1 000 kg/m^3 = 0.6 m^3
The volume of the displaced fluid equals the volume of the portion of the barge sinked, wich is the area of the rectangular base times the depth to which it sinked>
7m*2m*H = 0.6 m^3 => H = 0.6 m^3 /[14 m^2] = 0.043 m = 4.3 cm
Answer: 4.3 cm
