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4 years ago

A temperature if 273 k is the temperature at which water

2 answers:

6 0

Degrees Celcius = Degrees Kelvin - 273

Therefor 273 K is equal to 0 degrees Celcius 

(the temperature at which water freezes)

olchik [2.2K]4 years ago

5 0

...at which water freezes.It is same as 0C°.

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If the wavelength of a wave is 2.5 m, and its frequency is 3 Hz, what is its speed?

castortr0y [4]

7.5m/s (2.5 x 3) c = frequency x wavelength

3 0

3 years ago

A 60kg block is at rest on a ramp inclined at 35 degrees.

weeeeeb [17]

Answer:

Explanation:

(a)Gravitational Force is W=mg

Frictional force is f

Normal force is N

(b)Since the block is in Equilibrium therefore from diagram we can see that

$f=mg\sin \theta$

$f=60\times 9.8\times \sin 35$

$f=337.26 N$

(c)Magnitude of Normal Force

$N=mg\cos \theta =481.66 N$

(d)friction is also given by

$f=\mu mg\cos \theta$

and $f=mg\sin \theta$

thus $tan \theta =\mu$

$\mu =0.7$

8 0

3 years ago

Purse-seine fishing is known to be the safest fishing method for protecting dolphins.

Citrus2011 [14]

Purse-seine fishing is known to be the safest fishing method for protecting dolphins.

This is false. This type of fishing method has been most blamed for the unintentional death of dolphins.

4 0

4 years ago

Read 2 more answers

Identify the stages of the water cycle where water moves downward from the force of gravity

hoa [83]

Umm I think that it's called a run off! Because it's running off of a surface into water.

8 0

3 years ago

Read 2 more answers

You throw a ball straight up with an initial velocity of 15.0 m/s. It passes a tree branch on the way up at a height of 7.00 m.

Gwar [14]

Answer:

0.95 seconds

Explanation:

t = Time taken

u = Initial velocity = 15 m/s

v = Final velocity

s = Displacement

a = Acceleration = 9.81 m/s² (downward positive, upward negative)

Time taken by the ball to reach the maximum height

$v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{0-15}{-9.81}\\\Rightarrow t=1.52\ s$

Maximum height

$v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-15^2}{2\times -9.81}\\\Rightarrow s=11.47\ m$

Distance between maximum height of the ball and the branch is 11.47-7 = 4.46 m

So, the distance that will be covered on the way down is 4.46 m

Now

u = 0

s = 4.46

$s=ut+\frac{1}{2}at^2\\\Rightarrow 4.46=0\times t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{4.46\times 2}{9.81}}\\\Rightarrow t=0.95\ s$

Time taken by the ball from the maximum height to the tree branch is 0.95 seconds.

Total time taken from the moment the ball is thrown to reach the tree branch is 1.52+0.95 = 2.47 seconds

7 0

3 years ago