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raketka [301]
3 years ago
12

CAN SOMEONE HELP ME PLEASE!? After chasing its prey, a cougar leaves skid marks that are 236 m in length. Assuming the cougar sk

idded to a complete stop with a constant acceleration of -2.87 m/s^2, identify the speed of the cougar before it began to skid.​
Physics
1 answer:
malfutka [58]3 years ago
5 0

Answer:

u=36.8m/s

Explanation:

because of the acceleration is a constant acceleration we can use one of the "SUVAT" equations

u^2=v^2-2ā*s. where:

u^2 stands for intial velocity

v^2 stands for final velocity

since the cougar skidded to a complete stop the final velocity is zero.

u^2=v^2-2ā*s

u^2=(0)^2 -2(-2.87 m/s^2)*236 m

u^2=0+5.74m/s^2* 236m

u^2=1354.64m^2/s^2

u=√1354.64m^2/s^2

u=36.8m/s (approximate value)

when ever the acceleration is constant you can use one of the following equation to find the required value.

1. v = u + at. (no s)

2. s= 1/2(u+v)t. (no ā)

3. s=ut + 1/2at^2. ( no v)

4. v^2=u^2 + 2āS. (no t). 5. s= vt - 1/2at^2. (no u)

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Computer simulation is useful because it helps in the prediction of what will likely happen in the future using data from past events.

<h3>What is computer simulation?</h3>
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Computer simulations are useful in studying phenomena in the universe because they help us to achieve the followings;

  • It helps in the prediction of what will likely happen in the future using data from past events.
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3 years ago
Read 2 more answers
Physics question, help please!
vova2212 [387]

The change in potential energy when the block falls to ground is -480J.

The maximum change in kinetic energy of the ball is 480 J.

The initial kinetic energy of the ball is 0 J.

The final  kinetic energy of the ball is 0.148J.

The initial potential energy of the ball is 0.187 J.

The final  potential energy of the ball is 0 J.

The work done by the air resistance is 0.039 J.

<h3>Change in potential energy when the block falls to ground</h3>

ΔP.E = -mgh

ΔP.E = -Wh

ΔP.E = - 40 x 12

ΔP.E = -480 J

<h3>Maximum change in kinetic energy of the ball</h3>

ΔK.E = - ΔP.E

ΔK.E = - (-480 J)

ΔK.E = 480 J

<h3>Initial kinetic energy of the ball</h3>

K.Ei = 0.5mv²

where;

  • v is zero since it is initially at rest

K.Ei = 0.5m(0) = 0

<h3>Final kinetic energy</h3>

K.Ef =  0.5mv²

K.Ef = 0.5(0.0091)(5.7)²

K.Ef = 0.148 J

<h3>Initial potential energy of the ball</h3>

P.Ei = mghi

P.Ei = 0.0091 x 9.8 x 2.1

P.Ei = 0.187 J

<h3>Final potential energy</h3>

P.Ef = mghf

P.Ef = 0.0091 x 9.8 x 0

P.Ef = 0

<h3>Work done by the air resistance</h3>

W = ΔE

W = P.E - K.E

W = 0.187 J - 0.148 J

W = 0.039 J

Learn more about potential energy here: brainly.com/question/1242059

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7 0
1 year ago
Which two quantities can be used to describe motion? A: Displacement and weight. B: speed and acceleration. C: speed and mass. D
HACTEHA [7]
The answer is B as all the other options contain quantities not related to describing motion
3 0
2 years ago
David moves a 350 N bucket with 175 N of force using a pulley. What mechanical advantage does he have when using the pulley?
NikAS [45]

Answer:

the mechanical advantage David had when using the pulley is 2.

Explanation:

Given;

load moved by David, L = 350 N

effort applied by David, E = 175 N

The mechanical advantage David had when using the pulley is calculated as;

M.A = \frac{Load}{Effort} \\\\M.A = \frac{350}{175} \\\\M.A = 2

Therefore, the mechanical advantage David had when using the pulley is 2.

7 0
3 years ago
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