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3 years ago

The charge per unit length on a long, straight filament is -92.0 μC/m. Find the electric field 10.0 cm above the filament.

Physics

1 answer:

Pepsi [2]3 years ago

4 0

Answer:

E = 1.655 x 10⁷ N/C towards the filament

Explanation:

Electric field due to a line charge is given by the expression

E = $[tex]\frac{\lambda}{2\pi\times\epsilon_0\times r}$ [/tex]

where λ is linear charge density of line charge , r is distance of given point from line charge and ε₀ is a constant called permittivity and whose value is

8.85 x 10⁻¹².

Putting the given values in the equation given above

E = $\frac{92\times10^{-6}}{2\times3.14\times8.85\times10^{-12}\times10^{-1}}$

E = 1.655 x 10⁷ N/C

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Even when the head is held erect, as in the figure below, its center of mass is not directly over the principal point of support

alexandr1967 [171]

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What is the chemical formula for dicarbon hexafluoride?

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Answer:

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3 years ago

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alekssr [168]

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Hook's law states that:

$F=k\Delta x$ (1)

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In this problem:

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$F=mg=(2.0 kg)(9.8 m/s^2)=19.6 N$

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$\Delta x=15 cm-10 cm=5 cm=0.05 m$

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Tems11 [23]

I notice that even though we're working with frames of reference
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In fact ! You didn't even say which frame the '12 km/hr' of his
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