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saul85 [17]
3 years ago
12

The charge per unit length on a long, straight filament is -92.0 μC/m. Find the electric field 10.0 cm above the filament.

Physics
1 answer:
Pepsi [2]3 years ago
4 0

Answer:

E = 1.655 x 10⁷ N/C towards the filament

Explanation:

Electric field due to a line charge is given by the expression

E = [tex]\frac{\lambda}{2\pi\times\epsilon_0\times r}[/tex]

where λ is linear charge density of line charge , r is distance of given point from line charge and ε₀ is a constant called permittivity and whose value is

8.85 x 10⁻¹².

Putting the given values in the equation given above

E = \frac{92\times10^{-6}}{2\times3.14\times8.85\times10^{-12}\times10^{-1}}

E = 1.655 x 10⁷ N/C

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Vesnalui [34]

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P = 450 J

Explanation:

Given that,

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We need to find the decrease in gravitational potential energy of the child sliding from the  top to the bottom of the slide.

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P = 18 kg × 10 m/s² × 2.5 m

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3 years ago
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Build up of pressure between tectonic plates .
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Which of the following is a zone found in the open ocean
Svetlanka [38]
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A 26 kg body is moving through space in the positive direction of an x axis with a speed of 350 m/s when, due to an internal exp
Gnom [1K]

Answer:

a.) 1567.2 m/s

b.) 149.4 m/s

Explanation:

Given that a 26 kg body is moving through space in the positive direction of an x axis with a speed of 350 m/s when, due to an internal explosion, it breaks into three parts. One part, with a mass of 7.8 kg, moves away from the point of explosion with a speed of 180 m/s in the positive y direction. A second part, with a mass of 8.8 kg, moves in the negative x direction with a speed of 640 m/s.

The x-component of the third part can be calculated by assuming that it moves in a positive x axis.

The third mass = 26 - ( 7.8 + 8.8)

The third mass = 26 - 16.6

The third mass = 9.4kg

since momentum is conserved, the momentum before explosion will be equal to sum of the momentum after explosion

26 x 350 = -8.8 x 640 + 9.4V

9100 = -5632 + 9.4V

9.4V = 9100 + 5632

9.4V = 14732

V = 14732/9.4

V = 1567.2 m/s

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1404 = 9.4V

V = 1404/9.4

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7 0
3 years ago
3 A 100 g steel ball falls from a height of 1.8 m on to a metal plate and rebounds to a height of 1.25 m.​
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Given values:

Mass of the steel ball, m = 100 g = 0.1 kg

Height of the steel ball, h1 = 1.8 m

Rebound height, h2 = 1.25 m

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1.764 Joules

b. KE = PE ->

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c. KE= 1/2 mv square

so v = square root 2ke/m

square root 2 x 1.764/ 0.1

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3 years ago
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