Answer:
look up the number (phone number) to call them and ask is they can cancel the account the debit card is abt to pay for :)
The author uses the text structure of compare and contrast to show multiple signals.
<h3>What is Text structures?</h3>
This is a term that connote the method used by authors to put together information in text.
Note that in the case above, The author uses the text structure of compare and contrast to show multiple signals.
Learn more about text structure from
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Well the result shown in C19 will show the sum of all cells from C5 to C18:
ie: C5 + C6+ C7+ C8+ C9+ C10+ C11+ C12+ C13+ C14+ C15+ C16+ C17+ C18
:)
It can approximately be around 20 basically it depends on your text how long or short the text is
Answer:
C++ code explained below
Explanation:
#include<bits/stdc++.h>
#include <iostream>
using namespace std;
int FiboNR(int n)
{
int max=n+1;
int F[max];
F[0]=0;F[1]=1;
for(int i=2;i<=n;i++)
{
F[i]=F[i-1]+F[i-2];
}
return (F[n]);
}
int FiboR(int n)
{
if(n==0||n==1)
return n;
else
return (FiboR(n-1)+FiboR(n-2));
}
int main()
{
long long int i,f;
double t1,t2;
int n[]={1,5,10,15,20,25,30,35,40,45,50,55,60,65,70,75};
cout<<"Fibonacci time analysis ( recursive vs. non-recursive "<<endl;
cout<<"Integer FiboR(seconds) FiboNR(seconds) Fibo-value"<<endl;
for(i=0;i<16;i++)
{
clock_t begin = clock();
f=FiboR(n[i]);
clock_t end = clock();
t1=double(end-begin); // elapsed time in milli secons
begin = clock();
f=FiboNR(n[i]);
end = clock();
t2=double(end-begin);
cout<<n[i]<<" "<<t1*1.0/CLOCKS_PER_SEC <<" "<<t2*1.0/CLOCKS_PER_SEC <<" "<<f<<endl; //elapsed time in seconds
}
return 0;
}
