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3 years ago

Which is equivalent to 2 5/6A. 5/3B. 7/6C. 17/6D. 12/5

Mathematics

2 answers:

Dimas [21]3 years ago

8 0

The answer would be C (17/6)
This is because;
6 goes into 17 twice leaving a reminder of 5.

RSB [31]3 years ago

8 0

Convert 2 5/6 into an improper fraction by multiplying 6 and 2 then adding 5. Keep the same denominator. The improper fraction would be 17/6. So your answer would be, C, 17/6.

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Subtract5x2 + 10x<br> 1 from 6x2<br> x + 3.

mixer [17]

Answer:

$-6x^{3} +5x^{2} +10x+3$

Step-by-step explanation:

5x^2+10x^1−6x^2x+3

=5x^2+10x+−6x^3+3

Answer:

=−6x^3+5x^2+10x+3

3 0

3 years ago

What is 9/32 + 7/8 plz help

Furkat [3]

Answer:

1 5/32

Step-by-step explanation:

First, find common denominators. What you do to the denominator, you must do to the numerator.

First, multiply 4 to both the numerator and denominator of the second fraction:

(7/8)(4/4) = (7 * 4)/(8 * 4) = 28/32

Next, add across:

9/32 + 28/32 = 37/32

Simplify. Turn the improper fraction into a mixed fraction:

37/32 = (32 + 5)/32 = 1 5/32

1 5/32 is your answer.

4 0

3 years ago

Read 2 more answers

Approximately how many times greater is 6 x 10^-5 than 5 x 10^-9

8_murik_8 [283]

Answer: $6 \times 10^{-5}$ is $1.2 \times 10^4.$ times greater than $5 \times 10^{-9}$ .

Step-by-step explanation:

We are given two numbers.

First number : $6 \times 10^{-5}$ .

Second number : $5 \times 10^{-9}$ .

In order to find how many times $6 \times 10^{-5}$ is greater than $5 \times 10^{-9}$ , we need to divide first number by second number.

Therefore,

$6 \times 10^{-5}$ ÷ $5 \times 10^{-9}$

or $\frac{6 \times 10^{-5}}{5 \times 10^{-9}}$

First we would divide 6 by 5.

On dividing 6 by 5, we get 1.2.

Now, we would divide 10^-5 by 10^-9.

In order to divide them, we can apply quotient rule of exponents $\frac{a^m}{a^n} =a^{m-n}$ .

We get

$\frac{10^{-5}}{10^{-9}} = 10^{-5-(-9)} = 10^{-5+9} = 10^4$ .

Therefore,

$\frac{6 \times 10^{-5}}{5 \times 10^{-9}}$ = $1.2 \times 10^4.$

So, we could say finally $6 \times 10^{-5}$ is $1.2 \times 10^4.$ times greater than $5 \times 10^{-9}$ .

8 0

3 years ago

Please help me with this!!!!

irinina [24]

Answer: A.

Step-by-step explanation: this is the answer because, look for keywords, in the sentence thay used the word WITHDREW which is also known as taking away, EX: withdrew= take away, divide, minus

Hope this helps!

8 0

2 years ago

Read 2 more answers

Factor each polynomial x^2-9x+10 <br> Show your work

jok3333 [9.3K]

Answer:

not factorable

Step-by-step explanation:

$x^{2} - 9x +10\\$

The easiest way to factor is to find two numbers of the "a" value (the coefficient before $x^{2}$ ) and the factors of the c value (10) that ADD up to give you -9, in this case it would be:

1 -10 --> 1(-10) gives you -10

1 -1 --> 1(-1) gives you -1

adding these together -10 + (-1) = -11 which does not equal -9.

You could stop here and conclude that this is not factorable by inspection.

Another method: using the quadratic formula to find its roots.

Roots: $(\frac{9-\sqrt{41} }{2}, 0)$ and $(\frac{9+\sqrt{41}}{2}, 0)$

7 0

2 years ago