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artcher [175]
2 years ago
6

If the voltage and resistance in a circuit both double, what happens to the current? use ohm’s law to explain your answer.

Physics
1 answer:
Allisa [31]2 years ago
4 0

One form of Ohm's law says:

                           Current  =  (voltage) / (resistance)

The voltage and resistance are the numerator and denominator
of the same fraction.  So if both of them double, the value of the
fraction doesn't change.

Nothing happens to the current.  It doesn't change.
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When the tube is filled with mercury vapor, as in this case, a sharp drop in the collected current is observed when the accelera
Nata [24]

Answer:

The energy absorbed by the atomic electrons in the mercury atom is 7.84 \times 10^{-19} J

Explanation:

Given:

Potential V = 4.9 V

According to the conservation law,

   Loss in kinetic energy = Gain in potential energy

Here, energy absorbed by the atomic electrons is given by,

    E = eV

Where e = 1.6 \times 10^{-19} C       ( charge of electron )

    E = 1.6 \times 10^{-19 } \times 4.9

    E = 7.84 \times 10^{-19} J

Therefore, the energy absorbed by the atomic electrons in the mercury atom is 7.84 \times 10^{-19} J

5 0
2 years ago
after a circuit has been turned off, so it is important to make sure they are discharged before you touch them. Suppose a 120 mF
Snezhnost [94]

Answer:

The time is 110.16\times10^{-3}\ sec

Explanation:

Given that,

Capacitor = 120 μF

Voltage = 150 V

Resistance = 1.8 kΩ

Current = 50 mA

We need to calculate the discharge current

Using formula of discharge current

i_{0}=\dfrac{V_{0}}{R}

Put the value into the formula

i_{0}=\dfrac{150}{1.8\times10^{3}}

i_{0}=83.3\times10^{-3}\ A

We need to calculate the time

Using formula of current

i=\dfrac{V_{0}}{R}e^{\frac{-t}{RC}}

Put the value into the formula

50=\dfrac{150}{1.8\times10^{3}}e^{\frac{-t}{RC}}

\dfrac{50}{83.3}=e^{\frac{-t}{RC}}

\dfrac{-t}{RC}=ln(0.600)

t=0.51\times1.8\times10^{3}\times120\times10^{-6}

t=110.16\times10^{-3}\ sec

Hence, The time is 110.16\times10^{-3}\ sec

4 0
3 years ago
A railroad car of mass 2.50*10^4 kg is moving with a speed of 4.00 m/s. It collides and couples with three other coupled railroa
NemiM [27]

Answer:

(a) 2.5 m/s

(b) 37.5 KJ

Explanation:

(a)

From the law of conservation of momentum, Initial momentum=Final momentum

mV_1+3mV_2=(m+3m)V_f=4mV_f

V_1+3V_2=4V_f and making V_f the subject then

V_f=\frac {V_1+3V_2}{4} and since V_1 is initial velocity of car, value given as 4 m/s, V_2 is the initial velocity of the three cars stuck together, value given as 2 m/s and v_f is the final velocity which is unknown. By substitution

V_f=\frac {4+(3\times2)}{4}=2.5 m/s

(b)

Initial kinetic energy is given by

\frac {mV_1^{2}}{2}+\frac {3mV_2^{2}}{2}=\frac {m(V_1^{2}+3V_2^{2}}{2}=\frac {2.5\times 10^{4}(4^{2}+3(2^{2}))}{2}=350\times10^{3} J= 350 KJ

Final kinetic energy is given by

\frac {4mV_f^{2}}{2}=\frac {4\times 2.5\times 10^{4}\times 2.5^{2}}{2}=312.5\times 10^{3} J=312.5 KJ

The energy lost is given by subtracting the final kinetic energy from the initial kinetic energy hence

Energy lost=350-312.5=37.5 KJ

6 0
3 years ago
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100. (: hope this helps
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