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Lera25 [3.4K]
3 years ago
15

A train travels 120 km In 2 hours and 30 minutes what’s its average speed

Physics
2 answers:
dangina [55]3 years ago
8 0
Formula for distance is d=st
so for speed is s=d/t 
 48 km per hour
Sedaia [141]3 years ago
5 0
Speed= distance / time or s=d/t.

120 / 2.5 (2.5 is 2 hours and 30 minutes.) = 48 km/h
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In one experiment, a student rolls a 2 kg ball such that it collides with a wall with a force of 10,000 N. In a second experimen
Brums [2.3K]

Answer:

(c) The wall exerts a greater force on the 2 kg ball than on the 5 kg ball since the force from the wall on each ball is equal to the force that each ball exerts on the wall.

Explanation:

According to Newton's third law of motion,"action and reaction are equal and opposite".

If a 2 kg ball exerts a force of 10,000 N on a wall, the wall will also exert a force of 10,000 N on the 2 kg ball but in opposite direction.

Similarly, If a 5 kg ball exerts a force of 5,000 N on a wall, the wall will also exert a force of 5,000 N on the 5 kg ball but in opposite direction.

Regardless of mass of the ball, the wall will exert equal force with which the ball collide with it.

Therefore, the wall exerts a greater force on the 2 kg ball than on the 5 kg ball since the force from the wall on each ball is equal to the force that each ball exerts on the wall.

8 0
3 years ago
How much higher is 0.25 meters than 0.0254 meters (with real objects)
sineoko [7]

Answer:

0.2246 meters

Explanation:

.25-0.0254 meters = 0.2246 meters

6 0
3 years ago
The water from a fire hose follows a path described by y equals 3.0 plus 0.8 x minus 0.40 x squared ​(units are in​ meters). If
ivanzaharov [21]

Explanation:

It is given that, the water from a fire hose follows a path described by equation :

y=3+0.8x-0.4x^2........(1)

The x component of constant velocity, v_x=5\ m/s

We need to find the resultant velocity at the point (2,3).

Let \dfrac{dx}{dt}=v_x and \dfrac{dy}{dt}=v_y

Differentiating equation (1) wrt t as,

\dfrac{dy}{dt}=0.8\times \dfrac{dx}{dt}-0.8x\times \dfrac{dx}{dt}

v_y=0.8\times v_x-0.8x\times v_x

v_y=0.8v_x(1-x)

When x = 2 and v_x=5\ m/s

So,

v_y=0.8\times 5\times (1-2)

v_y=-4\ m/s

Resultant velocity, v=\sqrt{v_x^2+v_y^2}

v=\sqrt{5^2+(-4)^2}

v = 6.4 m/s

So, the resultant velocity at point (2,3) is 6.4 m/s. Hence, this is the required solution.

8 0
3 years ago
Help meeeeeeeeeeee!!!!
Evgesh-ka [11]

Answer:D 780,000,000km

Explanation:

1 AU is the distance of the sun to the earth and this value is 150,000,000km

Jupiter's distance from the sun is 5.2AU and is equivalent in km is:

5.2AU × 150,000,000Km= 780,000,000km

4 0
3 years ago
What happened to the washer when the car was stopped by the textbook?
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Car stopped im not sure
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2 years ago
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