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Lera25 [3.4K]
3 years ago
15

A train travels 120 km In 2 hours and 30 minutes what’s its average speed

Physics
2 answers:
dangina [55]3 years ago
8 0
Formula for distance is d=st
so for speed is s=d/t 
 48 km per hour
Sedaia [141]3 years ago
5 0
Speed= distance / time or s=d/t.

120 / 2.5 (2.5 is 2 hours and 30 minutes.) = 48 km/h
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An astrophysicist mounts two thin lenses along a single optical axis (the lenses are at right angles to the line connecting them
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Answer:

1 / i + 1 / o = 1 / f     thin lens equations

i = o f / (o - f)   rearranging

Lens 1:   object = 30 cm    f = 15.2 cm

i1 = 30 * 15.2 / (30 - 15.2) = 30.8 cm

o2 = 40.2 - 30/8 = 9.4 cm    distance of image 1 from lens 2

i2 = 9.4 * 15.2 / (9.4 - 15.2) = - 24.6 cm

The final image is 24.6 cm to the left of lens 2

The first image is inverted

The second image is erect (as seen from the first image)

So the final image is inverted

M = m1 * m2 = (-30.8 / 30) * (24.6 / 9.4) = -2.69

7 0
3 years ago
Two blocks are connected by a string over a pulley. The hanging block has a mass of 8-kg and the one on the plane has a mass of
jeka94

Answer:

Let f be force of friction on the blocks kept on inclined plane. T be tension in the string

For motion of block on the inclined plane in upward direction

T - m₁gsin40 - f = m₁a

f = μ m₁gcos40

For motion of hanging  block on  in downward direction

m₂g  - T = m₂ a

Adding to cancel T

m₂g - - m₁gsin40 -  μ m₁gcos40 = a ( m₁+m₂ )

a =   g (m₂ - - m₁sin40 -  μ m₁cos40) / ( m₁+m₂ )

Putting the values

a = 9.8 ( 4.75 - 2.12-1.045) / 7.6

2.04 m s⁻²

M₂ will go down and M₁ will go up with acceleration .

Explanation:

7 0
3 years ago
2) A car going down the road has a velocity of 20 m/s. If the car continues at this
Artemon [7]

Answer: 140

Explanation: just multiply 7 x 20

5 0
3 years ago
Read 2 more answers
If Cell fragments are found in a rock sample it was most likely that The Rock formed
Ira Lisetskai [31]
5 is  4) shallow water, 6 is 2)sedimentary i think but I'm not 100% sure and 7 is 21%
7 0
4 years ago
Two objects, one having twice the mass of the other, are initially at rest. Two forces, one twice as big as the other, act on th
Elodia [21]

<em><u>Note: There is no image to take as a reference, so I'm assuming F2 directed to the right and F1 to the left, and F2=2F1</u></em>

Answer:

\displaystyle a=\frac{F}{3M}

<em>to the right</em>

Explanation:

<u>Net Force</u>

When several forces are applied to a particle or a system of particles, the net force is the sum of them all, considering each force as a vector. As for the second Newton's law, the total force equals the product of the mass by the acceleration of the system:

\vec F_n=m\cdot \vec a

If the net force is zero, then the system of particles keeps at rest or at a constant velocity.

The system of particles described in the question consists of two objects of masses m1=M and m2, where

m_2=2m_1=2M

Two forces F1=F and F2 act individually on each object in opposite directions and

F_2=2F_1=2F

We don't get to see any image to know where the forces are applied to, so we'll assume F2 to the right and F1 to the left.

The net force of the system of particles is

F_n=2F-F=F

The mass of the system is

m_t=m_1+m_2=3M

Thus, the acceleration of the center of mass of the system is

\displaystyle a=\frac{F}{3M}

Since F2 is greater than F1, the direction of the acceleration is to the right.

Note: If the forces were opposite than assumed, the acceleration would be to the left

6 0
3 years ago
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