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Deffense [45]
2 years ago
7

Omparing Technological Design and Scientific Investigation

Physics
1 answer:
djyliett [7]2 years ago
6 0

Answer:

杰恩斯克克斯克奇沃伊斯克克斯克什德布德克什恩克恩德恩克恩茨克杰兹姆克斯恩斯姆斯姆德恩德姆德武伊乔奥斯克斯杰德布德赫德夫赫富伊什杰吉迪赫德赫夫赫德

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Anika asks Eva to roll a basketball and then a bowling ball to her. Which requires more force to roll, and why?
Contact [7]
The bowling ball will require more force to roll because it is more massive.
3 0
2 years ago
Read 2 more answers
A mover pushes a 46.0kg crate 10.3m across a rough floor without acceleration. How much work did the mover do (horizontally) pus
Alchen [17]

Answer:

<h3>2,321.62Joules</h3>

Explanation:

The formula for calculating workdone is expressed as;

Workdone = Force * Distance

Get the force

F = nR

n is the coefficient of friction = 0.5

R is the reaction = mg

R = 46 ( 9.8)

R = 450.8N

F = 0.5 * 450.8

F = 225.4N

Distance = 10.3m

Get the workdone

Workdone = 225.4 * 10.3

Workdone  = 2,321.62Joules

<em>Hence the amount of work done is 2,321.62Joules</em>

3 0
3 years ago
A snail can move approximately 0.30 meters per minute.how many meters can the snail cover in 15 minutes?
ololo11 [35]

Answer:

4.5 meters is your Answer goood luck please give 5 star

Explanation:

3 0
2 years ago
A box is placed on a table. If an upward pulling force on the box is slightly less than the weight of the box, what will happen
aniked [119]

Answer:

<u><em>A for certain.</em></u>

Explanation:

I got it right on the test, thanks to the other brainly answerer teresecaway. But knowing the answer doesnt help much if you dont know WHY. The reason WHY is as follows. At first you might think it would be B, because the downwards force is greater than the upwards force. I thought that maybe upwards force would also count as the table supporting it, but no, thats just structural inanimate solid table. The answer is A. gravity would have to be HIGHLY raised or somebody pressing down on it, to make it fall through the table.

5 0
2 years ago
If a drop is to be deflected a distance d = 0.350 mm by the time it reaches the end of the deflection plate, what magnitude of c
Sloan [31]

Answer:

q = 4.87 X 10^ -14 C

Explanation:

As d=0.350 mm

The ink drop will be accelerated by the electric field between the plates:

a = F/m

d = a(D0 / v)^2 / 2 ...... 1

a = qE/m ............... 2

Substituting 2  into 1:

d = (qE/m)(D0 / v)^2 / 2

q = 2mdv^2 / [E(D0)^2]

q = 2(1.00e-11 kg)(3.50e-4 m)(15.0 m/s)^2 / [(7.70e4 N/C)(2.05e-2 m)^2]

q = 4.87e-14 C

6 0
3 years ago
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