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Zina [86]
3 years ago
8

A strand of 10 lights is plugged into an outlet. How can you determine if the lights are connected in series or parallel? Select

all that apply.
Question 8 options:

1) Unscrew one light. If the other lights turn off, it's a series circuit.


2) Unscrew one light. If the other lights stay on, it's a series circuit.


3) Unscrew one light. If the other lights stay on, it's a parallel circuit.


4) Unscrew one light. If the other lights turn off, it's a parallel circuit.

Physics
1 answer:
ExtremeBDS [4]3 years ago
7 0

Answer:

1) True; 2) False; 3) True; 4) False

Explanation:

To better understand and solve this problem in an easier way, the attached diagram shows two circuits A & B. A is connected in series and B in parallel. In each of the circuits, we can see that different currents are generated, in the serial circuit, you have a single current, while the parallel circuit you have the main current plus two currents.

1)

This is true (for a series circuit) , when one of the bulbs is removed the only current that exists in the circuit is interrupted, so the other bulbs will not work.

2)

This is false, removing a light bulb involves interrupting the current, therefore no light bulb in this type of series circuits will continue its work.

3)

This is true, because when removing one of the bulbs, the current is not interrupted for the other bulbs, each has its own current.

4)

This is false, a circuit connected in parallel, allows the division of the current, in each of its loads, so each load will have its respective current.

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vagabundo [1.1K]
The momentum would increase assuming the velocity stays the same. P=Mv
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2 years ago
Give 1 real life example of a scenario that takes advantage of the inverse relationship between force and time when impulse is c
OverLord2011 [107]

Answer:

On real life example of a scenario that takes advantage of the inverse relationship between force and time when impulse is constant is when making a serve with a lawn tennis racket

How It is an example of impulse is that when a serve is made by moving the bat slowly, the lawn tennis player uses less force and the ball is in contact with the string for longer a period

When however, the lawn tennis player moves the racket faster, with the strings of the racket highly tensioned  he uses more force and the ball also spends less time on the racket to produce the same momentum

Explanation:

The impulse of a force, ΔP is given by the following formula;

ΔP = F × Δt

Where ΔP is constant, we have;

F ∝ 1/Δt

Therefore, for the same impulse, when the force is increased, the time of contact is decreases and vice versa.

7 0
3 years ago
A car has a mass of 1.00 × 103 kilograms, and it has an acceleration of 4.5 meters/second2. What is the net force on the car?
aksik [14]

ANSWER


C. F=4.5 \times10^3. newtons


EXPLANATION


According to Newton's second law,



F_{net}=ma, where



m=1.00\times 10^3kg is the mass measured in kilograms.


and


a=4.5ms^{2} is the acceleration in metres per second square.



We substitute these values to obtain,


F=1.00\times10^3 \times 4.5.



We rearrange to get,


F=1.00\times4.5 \times10^3.


We multiply out the first two numbers and leave our answer in standard form to get,



F=4.5 \times10^3 N.



The correct answer is C


3 0
3 years ago
Barbara places an object in front of a mirror. The mirror produces an image that is inverted, real, and smaller than the object.
Darya [45]

Concave is what your looking for

4 0
3 years ago
Read 2 more answers
A 4.79 g bullet moving at 642.3 m/s penetrates a tree trunk to a depth of 4.35 cm. Use work and energy considerations to find th
vladimir1956 [14]

Answer:

Force, F=2.27\times 10^4\ N

Explanation:

Given that,

Mass of the bullet, m = 4.79 g = 0.00479 kg

Initial speed of the bullet, u = 642.3 m/s

Distance, d = 4.35 cm = 0.0435 m

To find,

The magnitude of force required to stop the bullet.

Solution,

The work energy theorem states that the work done is equal to the change in its kinetic energy. Its expression is given by :

F.d=\dfrac{1}{2}m(v^2-u^2)

Finally, it stops, v = 0

F.d=-\dfrac{1}{2}m(u^2)

F=\dfrac{-mu^2}{2d}

F=\dfrac{-0.00479\times (642.3)^2}{2\times 0.0435}

F = -22713.92 N

F=2.27\times 10^4\ N

So, the magnitude of the force that stops the bullet is 2.27\times 10^4\ N

7 0
2 years ago
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