A strand of 10 lights is plugged into an outlet. How can you determine if the lights are connected in series or parallel? Select
all that apply.
Question 8 options:
1) Unscrew one light. If the other lights turn off, it's a series circuit.
2) Unscrew one light. If the other lights stay on, it's a series circuit.
3) Unscrew one light. If the other lights stay on, it's a parallel circuit.
4) Unscrew one light. If the other lights turn off, it's a parallel circuit.
Question 8 options:
1) Unscrew one light. If the other lights turn off, it's a series circuit.
2) Unscrew one light. If the other lights stay on, it's a series circuit.
3) Unscrew one light. If the other lights stay on, it's a parallel circuit.
4) Unscrew one light. If the other lights turn off, it's a parallel circuit.
1 answer:
Answer:
1) True; 2) False; 3) True; 4) False
Explanation:
To better understand and solve this problem in an easier way, the attached diagram shows two circuits A & B. A is connected in series and B in parallel. In each of the circuits, we can see that different currents are generated, in the serial circuit, you have a single current, while the parallel circuit you have the main current plus two currents.
1)
This is true (for a series circuit) , when one of the bulbs is removed the only current that exists in the circuit is interrupted, so the other bulbs will not work.
2)
This is false, removing a light bulb involves interrupting the current, therefore no light bulb in this type of series circuits will continue its work.
3)
This is true, because when removing one of the bulbs, the current is not interrupted for the other bulbs, each has its own current.
4)
This is false, a circuit connected in parallel, allows the division of the current, in each of its loads, so each load will have its respective current.
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Answer:
a) F_net = 6.48 10⁻¹⁸ ( ), b) x = 0.15 m
Explanation:
a) In this problem we use that the electric force is a vector, that charges of different signs attract and charges of the same sign repel.
The electric force is given by Coulomb's law
F =
Since when we have the two negative charges they repel each other and when we fear one negative and the other positive attract each other, the forces point towards the same side, which is why they must be added.
F_net= ∑ F = F₁ + F₂
let's locate a reference system in the load that is on the left side, the distances are
left side - electron r₁ = x
right side -electron r₂ = d-x
let's call the charge of the electron (q) and the fixed charge that has equal magnitude Q
we substitute
F_net = k q Q ( )
F _net = kqQ ( )
let's substitute the values
F_net = 9 10⁹ 1.6 10⁻¹⁹ 4.50 10⁻⁹ ( )
F_net = 6.48 10⁻¹⁸ ( )
now we can substitute the value of x from 0.05 m to 0.25 m, the easiest way to do this is in a spreadsheet, in the table the values of the distance (x) and the net force are given
x (m) F (N)
0.05 27.0 10-16
0.10 8.10 10-16
0.15 5.76 10-16
0.20 8.10 10-16
0.25 27.0 10-16
b) in the adjoint we can see a graph of the force against the distance, it can be seen that it has the shape of a parabola with a minimum close to x = 0.15 m
