A strand of 10 lights is plugged into an outlet. How can you determine if the lights are connected in series or parallel? Select
all that apply.
Question 8 options:
1) Unscrew one light. If the other lights turn off, it's a series circuit.
2) Unscrew one light. If the other lights stay on, it's a series circuit.
3) Unscrew one light. If the other lights stay on, it's a parallel circuit.
4) Unscrew one light. If the other lights turn off, it's a parallel circuit.
Question 8 options:
1) Unscrew one light. If the other lights turn off, it's a series circuit.
2) Unscrew one light. If the other lights stay on, it's a series circuit.
3) Unscrew one light. If the other lights stay on, it's a parallel circuit.
4) Unscrew one light. If the other lights turn off, it's a parallel circuit.
1 answer:
Answer:
1) True; 2) False; 3) True; 4) False
Explanation:
To better understand and solve this problem in an easier way, the attached diagram shows two circuits A & B. A is connected in series and B in parallel. In each of the circuits, we can see that different currents are generated, in the serial circuit, you have a single current, while the parallel circuit you have the main current plus two currents.
1)
This is true (for a series circuit) , when one of the bulbs is removed the only current that exists in the circuit is interrupted, so the other bulbs will not work.
2)
This is false, removing a light bulb involves interrupting the current, therefore no light bulb in this type of series circuits will continue its work.
3)
This is true, because when removing one of the bulbs, the current is not interrupted for the other bulbs, each has its own current.
4)
This is false, a circuit connected in parallel, allows the division of the current, in each of its loads, so each load will have its respective current.
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Hi there!
a)
Let's use Biot-Savart's law to derive an expression for the magnetic field produced by ONE loop.
dB = Differential Magnetic field element
μ₀ = Permeability of free space (4π × 10⁻⁷ Tm/A)
R = radius of loop (2.15 cm = 0.0215 m)
i = Current in loop (0.460 A)
For a circular coil, the radius vector and the differential length vector are ALWAYS perpendicular. So, for their cross-product, since sin(90) = 1, we can disregard it.
Now, let's write the integral, replacing 'dl' with 'ds' for an arc length:
Taking out constants from the integral:
Since we are integrating around an entire circle, we are integrating from 0 to 2π.
Evaluate:
Plugging in our givens to solve for the magnetic field strength of one loop:
Multiply by the number of loops to find the total magnetic field:
b)
Now, we have an additional component of the magnetic field. Let's use Biot-Savart's Law again:
In this case, we cannot disregard the cross-product. Using the angle between the differential length and radius vector 'θ' (in the diagram), we can represent the cross-product as cosθ. However, this would make integrating difficult. Using a right triangle, we can use the angle formed at the top 'φ', and represent this as sinφ.
Using the diagram, if 'z' is the point's height from the center:
Substituting this into our expression:
Now, the only thing that isn't constant is the differential length (replace with ds). We will integrate along the entire circle again:
Evaluate:
Multiplying by the number of loops:
Plug in the given values: