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Zina [86]
3 years ago
8

A strand of 10 lights is plugged into an outlet. How can you determine if the lights are connected in series or parallel? Select

all that apply.
Question 8 options:

1) Unscrew one light. If the other lights turn off, it's a series circuit.


2) Unscrew one light. If the other lights stay on, it's a series circuit.


3) Unscrew one light. If the other lights stay on, it's a parallel circuit.


4) Unscrew one light. If the other lights turn off, it's a parallel circuit.

Physics
1 answer:
ExtremeBDS [4]3 years ago
7 0

Answer:

1) True; 2) False; 3) True; 4) False

Explanation:

To better understand and solve this problem in an easier way, the attached diagram shows two circuits A & B. A is connected in series and B in parallel. In each of the circuits, we can see that different currents are generated, in the serial circuit, you have a single current, while the parallel circuit you have the main current plus two currents.

1)

This is true (for a series circuit) , when one of the bulbs is removed the only current that exists in the circuit is interrupted, so the other bulbs will not work.

2)

This is false, removing a light bulb involves interrupting the current, therefore no light bulb in this type of series circuits will continue its work.

3)

This is true, because when removing one of the bulbs, the current is not interrupted for the other bulbs, each has its own current.

4)

This is false, a circuit connected in parallel, allows the division of the current, in each of its loads, so each load will have its respective current.

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A boy rolls a toy car across a floor with a velocity of 3.21 m/s. How long does it take the car to travel a distance of 4.50 m?
Mariana [72]

Answer:

Time taken for the car to travel a distance of 4.50 m = 1.40 seconds

Explanation:

velocity of toy car = 3.21 m/s

distance travelled by toy car = 4.50 m

Time = ?

Velocity = \frac{Distance}{Time} \\Time =\frac{Distance}{Velocity}

Time = \frac{4.50}{3.21} \\Time = 1.40s

Therefore, the time taken for the car to travel a distance of 4.50 m = 1.40 seconds

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Is it possible to be moving but not be in motion?
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No. Motion is the thing that when you're moving, you're in it.

But it IS possible for one person to say you're moving and another person to say you're not moving, both at the same time, and both of them are correct !

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two 2.5 kg balls move away from each other one traveling 3 m/s to the right the other 4 m/s to the left what is the magnitude of
Juli2301 [7.4K]

Answer:

2.5 kg.m/s

Explanation:

Taking left side as positive while right side direction as negative then

Momentum, p= mv where m is the mass of the object and v is the velocity of travel

Momentum for ball moving towards right side=mv=2.5*-3=-7.5 kg.m/s

Momentum for the ball moving towards the left side=mv=2.5*4=10 kg.m/s

Total momentum=-7.5 kg.m/s+10 kg.m/s=2.5 kg.m/s

5 0
3 years ago
Uma carga puntiforme de + 3,0uC é colocada em um ponto P de um campo elétrico gerado por uma partícula eletrizada com carga desc
expeople1 [14]

Responda:

1) E = 6 × 10 ^ 6NC ^ -1 2) Q = 6 × 10 ^ -5

Explicação:

Dado o seguinte:

Carga (q) = 3uC = 3 × 10 ^ -6C

Força elétrica (Fe) = 18N

Intensidade do campo elétrico (E) =?

1)

Lembre-se:

Força elétrica (Fe) = carga (q) * Intensidade do campo elétrico (E)

Fe = qE; E = Fe / q

E = 18N / (3 × 10 ^ -6C)

E = 6N / 10 ^ -6C

E = 6 × 10 ^ 6NC ^ -1

2)

Lembre-se:

E = kQ / r ^ 2

E = intensidade do campo elétrico

Q = carga de origem

r = distância de espera = 30cm = 30/100 = 0,3m

K = 9,0 × 10 ^ 9

6 × 10 ^ 6 = (9,0 × 10 ^ 9 * Q) / 0,3 ^ 2

9,0 × 10 ^ 9 * Q = 6 × 10 ^ 6 * 0,09

Q = 0,54 × 10 ^ 6 / 9,0 × 10 ^ 9

Q = 0,06 × 10 ^ (6-9)

Q = 0,06 × 10 ^ -3

Q = 6 × 10 ^ -5 = 60 × 10 ^ -6 = 60μC

7 0
3 years ago
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