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2 years ago

An object buoyant force and wieght arent the smae thing

Physics

1 answer:

Alona [7]2 years ago

7 0

I hope this is true or false

The answer would be TRUE

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Some children are underfed and often have no place to sleep. According to

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Answer:

Physiological needs

Explanation:

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3 years ago

A horse runs around a circular track that is 350.0 m long. He runs clockwise from

Ivahew [28]

Answer:

A 0m

Explanation:

The horse runs clockwise round the strack, then goes back to the start line ending up back at the same place when it started.

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3 years ago

Read 2 more answers

Desperado, a roller coaster built in Nevada, has a mass of 800 kg. It also has a vertical drop of 225 feet down the first hill.

weeeeeb [17]

Answer:

the work done by friction on the car is 524,582 J.

Explanation:

Given;

mass of the roller coaster, m = 800 kg

distance moved by the coaster, d = 225 ft = 68.58 m

final velocity of the coaster, v = 80 mi/h = 35.76 m/s

The time taken for the coaster to drop down the hill is calculated as;

$t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\ \times \ 68.58}{9.8} } \\\\t = 3.74 \ s$

The work done by friction on the car is calculated as;

$W =F\ \times \ d = \frac{mv}{t} \times \ d\\\\W = \frac{800 \ \times \ 35.76 }{3.74} \times \ 68.58\\\\W = 524,582 \ J$

Therefore, the work done by friction on the car is 524,582 J.

6 0

3 years ago

Constructive interference definition physics

elena-14-01-66 [18.8K]

Answer:

the interference of two or more waves of equal frequency and phase, resulting in their mutual reinforcement and producing a single amplitude equal to the sum of the amplitudes of the individual waves.

8 0

3 years ago

A car travels in a flat circle of radius R. At a certain instant the velocity of the car is 24 m/s west and the total accelerati

lisov135 [29]

Answer with Explanation:

We are given that

Velocity,v=24 m/s west

Acceleration,a= $2.5m/s^2$

$\theta=53^{\circ}$ (N of W)

Horizontal component of acceleration=Tangential acceleration

Tangential acceleration, $a_x=acos\theta=2.5cos53=1.505 m/s^2$

Radial acceleration=Vertical acceleration= $a_y=asin\theta$

$a_y=2.5sin53=1.998 m/s^2$

Radial acceleration, $a_y=\frac{v^2}{R}$

$1.998=\frac{(24)^2}{R}$

$R=\frac{(24)^2}{1.998}$

$R=288.29 m$

Time, $t=\frac{2\pi R}{velocity}$

$t=\frac{2\pi(288.29)}{24}$

$t=75.47 s$

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3 years ago