A 1 kg ball and a 10 kg ball are dropped from a height of 10 m at the same time. In the absence of air resistance,
1 answer:
Answer:
the two balls will hit the ground at the same time.
Explanation:
The time of dropping, in the following equation, is related to both the distance travel s and the gravitational acceleration g, which are the same for both ball (if we neglect air resistance), no matter what their mass are.
So the time it takes to drop 2 balls are the same. They will hit the ground at the same time.
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Answer:
3.467 s
Explanation:
given,
distance , d = 49 mm = 0.049 m
initial speed of the of the rock, v = 17 m/s
time taken by the Heather rock to reach water
using equation of motion
taking downward as negative
4.9 t² + 17 t - 0.049 = 0
now,
t₁ = -3.47 s , 0.0028 s
rejecting negative values
t₁ = 0.0028 s
now, time taken by the ball of Jerry
using equation of motion
taking downward as negative
4.9 t² - 17 t - 0.049 = 0
now,
t₂ = 3.47 s ,-0.0028 s
rejecting negative values
t₂ = 3.47 s
now, time elapsed is = t₂ - t₁ = 3.47 - 0.0028 = 3.467 s