A 1 kg ball and a 10 kg ball are dropped from a height of 10 m at the same time. In the absence of air resistance,
1 answer:
Answer:
the two balls will hit the ground at the same time.
Explanation:
The time of dropping, in the following equation, is related to both the distance travel s and the gravitational acceleration g, which are the same for both ball (if we neglect air resistance), no matter what their mass are.
So the time it takes to drop 2 balls are the same. They will hit the ground at the same time.
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Answer:
a)
b)
Explanation:
Given:
mass of bullet,
compression of the spring,
force required for the given compression,
(a)
We know
where:
a= acceleration
we have:
initial velocity,
Using the eq. of motion:
where:
v= final velocity after the separation of spring with the bullet.
(b)
Now, in vertical direction we take the above velocity as the initial velocity "u"
so,
∵At maximum height the final velocity will be zero
Using the equation of motion:
where:
h= height
g= acceleration due to gravity
is the height from the release position of the spring.
So, the height from the latched position be: