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irinina [24]
3 years ago
8

What is a lenticular (S0) galaxy? A galaxy with a disk and central bulge like a spiral galaxy, but with no spiral arms A galaxy

with a smooth brightness profile, lacking the central bulge and disk of a spiral galaxy A spiral galaxy with fuzzy and poorly formed spiral arms A galaxy with a lot of gas and dust and no particular structure
Physics
1 answer:
RSB [31]3 years ago
6 0

Answer:

A galaxy with a disk and central bulge like a spiral galaxy, but with no spiral arms

Explanation:

A Lenticular galaxy is a kind of galaxy intermediate between elliptical galaxy and a spiral galaxy in the Morphological classification system of galaxies. They have a central bulge or disc just like a Spiral galaxy but lacks the arms of spiral galaxy. If looked edge on they appear to be spiral and if looked face on they appear to be elliptical.

The absence of spiral arms can be attributed to the absence of star formation. They mainly consists of ageing stars.

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gayaneshka [121]

Answer:

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Explanation:

8 0
3 years ago
Which of the following are basic principles that apply to circuits? Choose the 2 correct answers from the choices below.
marta [7]

The basic principles that apply to circuits is that electrons must receive energy from a source, and electrons transfer energy to perform some useful function.

<h3 /><h3>What is circuit?</h3>

Individual electronic components, like resistors, transistors, are connected by metallic wires or traces by which the electric current can flow to form a circuit design.

The basic principles that apply to circuits will be;

1. Electrons must receive energy from a source.

2. Electrons transfer energy to perform some useful function.

Hence, option 1 and 2 are correct.

To learn more about the circuit, refer to the link;

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5 0
2 years ago
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BartSMP [9]

Answer:

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4 0
4 years ago
A 2.61 g lead weight, initially at 11.1 ∘C, is submerged in 7.67 g of water at 52.6 ∘C in an insulated container. What is the fi
sleet_krkn [62]

Answer:

Equilibrium temperature will be T=52.2684^{\circ}C

Explanation:

We have given weight of the lead m = 2.61 gram

Let the final temperature is T

Specific heat of the lead c = 0.128

Initial temperature of the lead = 11°C

So heat gain by the lead = 2.61×0.128×(T-11°C)

Mass of the water m = 7.67 gram

Specific heat = 4.184

Temperature of the water = 52.6°C

So heat lost by water = 7.67×4.184×(T-52.6)

We know that heat lost = heat gained

So 2.61\times 0.128\times (T-11)=7.67\times 4.184\times (52.6-T)

0.334T-3.67=1688-32.031T

T=52.2684^{\circ}C

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3 years ago
Would a ship in Lake Ontario (fresh water) float higher or lower in the water than in the Atlantic Ocean (salt water)?
ohaa [14]

Atlantic Ocean (salt water)

8 0
3 years ago
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