Answer:
a) Initial velocity of the ball=14.5 m/s
b)The ball rise to a height of 10.72 m/s
c)The velocity of the ball is zero at the highest point.
Explanation:
Taking point at which the ball is thrown to be origin. Distanced measured to be positive in upwards directions.
a)
Now using equation of motion

The initial velocity of the ball is 
b) Let h be the height that ball rise above the starting point given by

c)The ball will be at rest with zero velocity at the highest point
Answer:
(a) 72.9 kg
Explanation:
Before the elevator starts to move, only gravitational force exerts on the man, this force is generated by the man mass and the gravitational acceleration, which in turn register in the scale. So the scale would probably indicate the man mass, which is 72.9 kg.
Complete Question


A galvanic cell based on these half-reactions is set up under standard conditions where each solutions is 1.00 L and each electrode weighs exactly 100.0 g. How much will the Cd electrode weigh when the non-standard potential of the cell is 0.03305 V?
Answer:
The mass is M= 117.37g
Explanation:
The overall reaction is as follows

The reaction is this way because the potential of
is higher than the potential of
so the the Fe would be oxidized and
would be reduced
At equilibrium the rate constant of the reaction is

![= \frac{[Fe^{2+}[Cd]]}{[Cd^{2+}][Fe]}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B%5BFe%5E%7B2%2B%7D%5BCd%5D%5D%7D%7B%5BCd%5E%7B2%2B%7D%5D%5BFe%5D%7D)
The Voltage of the cell 
Substituting the given values into the equation


The voltage of the cell at any point can be calculated using the equation

Where 
Substituting for Q
![E = E_{cell} - \frac{0.059}{n_e} \frac{[Fe^{2+}[Cd]]}{[Cd^{2+}][Fe]}](https://tex.z-dn.net/?f=E%20%3D%20E_%7Bcell%7D%20-%20%5Cfrac%7B0.059%7D%7Bn_e%7D%20%5Cfrac%7B%5BFe%5E%7B2%2B%7D%5BCd%5D%5D%7D%7B%5BCd%5E%7B2%2B%7D%5D%5BFe%5D%7D)
When E = 0.03305 V

Since we are considering the Cd electrode the equation becomes
![E= E_{cell} - \frac{0.059}{n_e} [\frac{1}{Cd^{2+}} ]](https://tex.z-dn.net/?f=E%3D%20E_%7Bcell%7D%20-%20%5Cfrac%7B0.059%7D%7Bn_e%7D%20%20%5B%5Cfrac%7B1%7D%7BCd%5E%7B2%2B%7D%7D%20%5D)
Substituting values and making [
] the subject
![[Cd^{2+}] =\frac{1}{e^{[\frac{0.03305- 0.038}{\frac{0.059 }{2} }] }}](https://tex.z-dn.net/?f=%5BCd%5E%7B2%2B%7D%5D%20%3D%5Cfrac%7B1%7D%7Be%5E%7B%5B%5Cfrac%7B0.03305-%200.038%7D%7B%5Cfrac%7B0.059%20%7D%7B2%7D%20%7D%5D%20%7D%7D)

Given from the question that the volume is 1 Liter
The number of mole = concentration * volume
= 0.8455 * 1
= 0.8455 moles
At the standard state the concentration of
is =1 mole /L
Hence the amount deposited on the Cd electrode would be
= Original amount - The calculated amount
= 1 - 0.8455
= 0.1545 moles
The mass deposited is mathematically represented as

The Molar mass of Cd 
Mass 

Hence the total mass of the electrode is = standard mass + calculated mass
M= 100+ 17.37
M= 117.37g
a > g , is the best shows the magnitude a and the direction of the ball's acceleration at time.
<h3>What is acceleration?</h3>
Acceleration is the rate at which the speed and direction of a moving object change over time. A point or object travelling in a straight path is accelerated if it accelerates or decelerates. Even if the speed is constant, motion on a circle is accelerated because the direction is always changing.
Given data
The velocity of the ball is: V
The angle of velocity with the horizontal is (θ) = 45
The acceleration of the ball is: a
The acceleration due to gravity is: g
When the hollow ball is projected into the air, air resistance will act on the ball that will slow down the ball's motion. Therefore the velocity direction is opposite to the reducing force. The reducing force relates to the opposite to the acceleration of the hollow ball.
F(delaying) ∝ -VF(delaying) ∝ m×a(r)×F(delaying) ∝ a(r)
Here m is the mass of the hollow ball.
The force of gravity on the ball which is acting downward given as:
F(gravity) ∝ g
So, a > g
Correct option: (B)
To know more about acceleration refer to:
brainly.com/question/460763
#SPJ1
This being a perfect collision means no energy is lost during the collision. Because this question asks for speed and not velocity, the speed will be the same because the final energy is the same. The speed after the collision would therefore be 1.27 m/s.