Answer:
0.107 m
Explanation:
The magnetic field at the center of a current-carrying loop is given by

where
is the vacuum permeability
I is the current
r is the radius of the loop
In this problem we have
I = 3.40 A is the current in the loop
is the magnetic field at the centre of the loop
So, solving the formula for r we find

Answer:
Both will reach to same height
Explanation:
Here we can see that friction is to be ignored
so we can say that work done by all the non conservative forces is change in mechanical energy
Since all non conservative forces here is zero
so mechanical energy is conserved here
so here we can say that sum of initial kinetic energy and potential energy = sum of final kinetic energy and potential energy
So we will have

now maximum height is given as

so here we can say that greatest height will be independent of the mass so they both will reach at same height
I think the answers are box #1 and #3. It is number one for a fact. However, it depends where the start is at #3.
Answer:
1.5024
Explanation:
Draw a diagram. Put the two cells in series. Now draw 3 resistors. Two of them equal 0.26 ohms each. The third one is the lightbulb which is 12 ohms.
R = 0.26 + 0.26 + 12 = 12.52
The bulb has a voltage of 2.88 volts across it. You can get the current from that.
i = E / R
i = 2.88 / 12 =
i = 0.24 amps.
Now you can get the voltage drop across the two cells.
E = ?
R = 0.26
i = 0.24 amps
E = 0.26 * 0.24
E = 0. 0624
Finally divide the 2.88 by 2 to get 1.44
Each cell has an emf of 1.44 + 0.0624 = 1.5024