Well, "speed" normally = (total distance covered) / (time to cover the distance).
In this case, we don't know the total distance that Santa has traveled, so the question can be answered only if we're willing to consider some other meaning of "speed".
Maybe we could say that in this case, "speed" means the average rate at which he visits houses. Then ...
Speed of visits = (total houses visited) / (time to visit them).
Speed of visits = (800 million houses) / (48 hours)
Speed of visits = 16.67 million houses per hour.
That's 277.8 thousand houses per minute
That's <em>4,630 houses per second</em>
Answer:
Acceleration, 
Explanation:
It is given that,
Time period of revolution of the moon, 
If the distance from the center of the moon to the surface of the planet is, 
The radius of the planet, 
Let a is the moon's radial acceleration. Mathematically, it is given by :
, R is the radius of orbit
Since, 
The radius of orbit is,
So, 
Hence, this is the required solution for the radial acceleration of the moon.
Answer:
B = 4.323 T
Explanation:
We are given;
Inner radius; r_i = 0.7 m
Number of turns; N = 890 turns
Current; I = 17 KA = 17000 A
Formula for the magnetic field inside the toroid along the inner radius is given by;
B = (μ_o × N × I)/(2πr)
μ_o is vacuum of permeability with a constant value of 4π × 10^(-7) H/m
Plugging in the relevant values, we have;
B = (4π × 10^(-7) × 890 × 17000)/(2 × π × 0.7)
B = (2 × 10^(-7) × 890 × 17000)/(0.7)
B = 4.323 T
Answer:
<h3>40.0 Joules. None of the answers is correct</h3>
Explanation:
Kinetic energy of an object is expressed as;
KE = 1/2mv² where;
m is the mass of the object
V is the velocity of the object.
Let Ma be the mass of the basketball and Mb be the mass of baseball.
If the mass of the basketball shown below is 4 times the mass of the baseball, then Ma = 4Mb
KE of the basket ball = 1/2MaVa²
Va² = 2(KE)a/Ma ...... 1
KE of the baseball = 1/2MbVb²
Vb² = 2(KE)b/Mb .......... 2
Since their velocities are the same, hence Va²= Vb²
2(KE)a/Ma = 2(KE)b/Mb
Substituting Ma = 4Mb into the resulting expression.
2(KE)a/4Mb = 2(KE)b/Mb
2(KE)a/4 = 2(KE)b
Given Kinetic energy of baseball (KE)b = 10.0J, the expression becomes;
2(KE)a/4 = 2(10)
2(KE)a = 4*20
2(KE)a = 80
(KE)a = 80/2
(KE)a = 40.0J
Hence the kinetic energy of the basketball is 40.0Joules
