Please help/show work!

1 answer:

3 0

Answer:

7.00335g

Explanation:

$n=\frac{V}{V_m} \\n = \frac{11.2}{22.4} \\n= 0.5 mol$

$n=\frac{m}{M} \\m=nM\\m=(0.5)(14.0067)\\m=7.00335g$

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