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tia_tia [17]
3 years ago
14

Two cars start from rest at a red stop light. When the light turns green, both cars accelerate forward. The blue car accelerates

uniformly at a rate of 3.8 m/s2 for 4.6 seconds. It then continues at a constant speed for 9.2 seconds, before applying the brakes such that the car’s speed decreases uniformly coming to rest 257.71 meters from where it started. The yellow car accelerates uniformly for the entire distance, finally catching the blue car just as the blue car comes to a stop.
How fast is the blue car going 2.8 seconds after it starts?

Physics
1 answer:
saul85 [17]3 years ago
4 0
First, create an illustration of the motion of the two cars as shown in the attached picture. The essential equations used is

For constant acceleration:
a = v,final - v,initial /t

The solutions is as follows:

 a = v,final - v,initial /t
 3.8 = (v - 0)/2.8 s
 v = 10.64 m/s
 After 2.8 seconds, the speed of the blue car is 10.64 m/s.

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A conveyor belt is used to send burgers through a grill- ing machine. If the grilling machine is 1.2m long and the burgers requi
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Answer:

Rate = 1.71 burger/min

Explanation:

Length of the conveyor belt is given as

L = 1.2 m

time taken to cook one burger is given as

t = 2.8 min = 168 s

now we can find the speed of the belt as

v = \frac{distance}{speed}

v = \frac{1.2}{168}

v = 7.14 \times 10^{-3} m/s

Now we know that the distance between two burgers is given as 25 cm

d = 0.25 m/burger

now the production rate of burgers is given as

Rate = \frac{v}{d}

Rate = \frac{7.14 \times 10^{-3} m/s}{0.25 m/burger}

Rate = 0.0286\frac{burger}{sec}

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3 years ago
For the circuit shown in the figure above, the correct procedure for measuring the resistance value of R1 is to
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Explain how electric current is able to flow
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Explanation:

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3 years ago
A ball is dropped from mystery height and it accelerates at 8m/s/s and it takes .9 seconds to hit the ground what is the height
geniusboy [140]

Answer:

The height of the drop is 3.24 m.

Explanation:

As the ball is dropped from a mystery height and it takes 0.9 seconds to hit the ground with the acceleration of 8 m/s2. Then the velocity with which the ball is thrown can be determined as

Velocity=Acceleration*Time

As the acceleration is 8 m/s2 and time is 0.9 s. Then

Velocity = 8*0.9=7.2 m/s

So we know, the velocity u = 7.2 m/s , acceleration a = 8 m/s2 and time taken to reach the ground as t = 0.9 s. Thus, the height of the drop will be equal to the displacement of the ball from the top to the ground. Thus with the help of second equation of motion, we can determine the height as height will be equal to displacement (s).

s=ut+\frac{1}{2}at^{2}

Thus,

s=(7.2*0)+(\frac{1}{2}*8*(0.9)^{2})=3.24 m

Thus, the height of the drop will be 3.24 m.

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