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Vladimir [108]
3 years ago
15

Name the following compound

Chemistry
2 answers:
const2013 [10]3 years ago
8 0

Answer:

bromine

Explanation:

hoefully this is right

Yuliya22 [10]3 years ago
8 0
Answer:
bromine
explanation: is in periodic table
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Place the particles in order from smallest to largest.
yulyashka [42]

Answer:

smallest to largest:

Electron, Neutron, Atom, Molecule, Nucleus

Explanation:

sorry if it's not right

7 0
3 years ago
Can someone please help me
Alona [7]

Answer:

Potassium iodide increases the decomposition rate of hydrogen peroxide.

Explanation:

Potassium iodide increases the decomposition rate of hydrogen peroxide because potassium iodide act as a catalyst. A catalyst speed up the process of chemical reaction without reacting with the molecules present in reaction. If the potassium iodide is not present as a catalyst for the decomposition of hydrogen peroxide then the decomposition of hydrogen peroxide takes too much time because the catalyst is absent that speed up the reaction.

5 0
3 years ago
Two completely different compounds may contain identical elements.<br><br> True<br> False
lesantik [10]
True. 

For example: Sodium oxide and Nitric acid; both compounds contain oxygen. 
7 0
3 years ago
A water sample has a pH of 8.2 and a bicarbonate concentration of 97 mg/L. What is the alkalinity of the sample in moles/L and i
goldfiish [28.3K]

Answer:6.94

Explanation:

Molar mass of CaCO3=40+12+16×3

=40+12+48=100g/mol

Moles=mass of substance/molar mass

=97mg/100g=0.097/100=0.00097moles/L.

PH=-log[CaCo3]=-log(0.00097)=6.94

P.s it's log to base e

3 0
3 years ago
If 23.6 g of hydrogen gas reacts with 28.3 g of nitrogen gas, what is the maximum amount of product that can be produced?
Aleonysh [2.5K]

Answer:

34.3 g NH3

Explanation:

M(H2) = 2*1 = 2 g/mol

M(N2) = 2*14 = 28 g/mol

M(NH3) = 14 + 3*1 = 17 g/mol

23.6 g H2* 1 mol/2 g = 11.8 mol H2

28.3 g N2 * 1 mol/28 g = 1.01 mol N2

                                 3H2 + N2 ------> 2NH3

from reaction         3 mol    1 mol

given                   11.8 mol    1.01 mol

We can see that H2 is given in excess, N2 is limiting reactant.

                                 3H2 + N2 ------> 2NH3

from reaction                     1 mol         2 mol

given                                 1.01 mol      x

x = 2*1.01/1= 2.02 mol NH3

2.02 mol * 17g/1 mol ≈ 34.3 g NH3

8 0
3 years ago
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