Answer:
SO₃(g) + H₂O(l) → H₂SO₄(aq)
Explanation:
The<em> molecular formula for the involved species</em> are:
- Sulfur trioxide = SO₃. ("trioxide" indicates the presence of 3 oxygen atoms).
With the above information in mind we can proceed to write the reaction equation:
- SO₃(g) + H₂O(l) → H₂SO₄(aq)
<span>STP means standard temperature
and pressure at 0°C (273K) and 1 atm (atmosphere). The density of the unknown
gas is 0.63 gram per liter. The deal gas equation is PV = nRT. The n is the
numer of moles and can be represented as mass of the gas, m, divided by the
molar mass, c. so we have,</span>
PV = nRT
PV = (m/c)RT
Since the density is d = m/V
Pc = (m/V)RT
Pc = dRT
c = drT/P
substitute the values into the equation,
c = [(0.63g/L)(0.08206
L-atm/mol-K)(273K)]/(1atm)
<u>c = 14.11 g/mol</u>
<span>The force of a system can be measured by formula P=mf where P is the force, m is the mass of the system and f is the acceleration of the system. The formula is known as Newton's second law of motion.</span>
According to law of definite proportion, for a compound, elements always combine in fixed ratio by mass.
The formula of compound remains the same, let it be a_{x}b_{y} where, a and b are two different elements.
Since, the ratio of mass remains the same , calculate the ratio of masses of element a and b in both cases
\frac{a}{b}=\frac{15}{35}=\frac{10}{y}
rearranging,
y=\frac{10\times 35}{15}=23.3
Thus, mass of b produced will be 23.3 g.
