I need some help on this.
2 answers:
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Answer:
Specific Rotation = 105º
S% in mixture = 92%
Explanation:
Specific rotation in organic compounds varies linearly, then the enantiomeric excess can be express as:
Where alpha is the specific rotation of the mixture and alpha pure is the specific rotation of the excess enantiomer.
Then, knowing that the S enantiomer is in excess you can calculate the specific rotation of that mixture:
For calculating the percentage of S you should remember that the enantiometric excess is the percentage of excess of a certain enantiomer, for example in this case:
Since S is in Excess
Also, it is true:
Then you can solve the system of linear equations, finding:
Hope it helps!