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Lina20 [59]
4 years ago
14

What two types of scientific knowledge can be expressed as mathematical equations? (Please don't tell me the answer could you pl

ease just follow me there. Thank you!)
Physics
1 answer:
gtnhenbr [62]4 years ago
5 0
An example would be 2 types of motion. It could be rectilinear or projectile motion. There are various equations for each type. Since you don't want me to tell you the answer, I could just express it in words. Then, it will be up to you to translate into mathematical equations.

For rectilinear motion, the distance traveled is equal to the initial velocity times the time, plus one-half of the acceleration times the square of the time. For projectile motion, the maximum distance is equal to the square of the initial velocity multiplied with the square of the sine of the launch angle, all over twice the gravity.
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A 1.83 kg1.83 kg book is placed on a flat desk. Suppose the coefficient of static friction between the book and the desk is 0.52
almond37 [142]

Answer:

9.4 N

Explanation:

m = mass of the book = 1.83 kg

\mu _{s} = Coefficient of static friction = 0.522

\mu _{k} = Coefficient of kinetic friction = 0.283

f_{s} = Static frictional force

F = force needed to make the book move

force needed to make the book move is same as the magnitude of maximum static frictional force applied by the desk on the book

Static frictional force is given as

f_{s} = \mu _{s} mg

Hence, the force need to move the book is given as

F = f_{s} = \mu _{s} mg

F = \mu _{s} mg

F = (0.522) (1.83 x 9.8)

F = 9.4 N

4 0
3 years ago
Where should you place the values of the independent variable when constructing a data table?
kobusy [5.1K]
<span>On the y-axis (the bottom of the table) hope this helps</span>
4 0
3 years ago
Read 2 more answers
A body starting from rest and moves with uniform acceleration. The velocities of the body are 40 m/s at the 4th second and 60 m/
Sergeeva-Olga [200]

Answer:

GIVEN

u is 40m/s and v=60m/s

time is 4s

therefore acceleration =60-40/4

=20/4=5m/s^2

b)next 2 sec=70m/s

8 0
3 years ago
Mary starts from her house, walks 80 meters south, and stops to chat with her aunt on the sidewalk. After chatting for a few min
Vaselesa [24]
The average speed will be:
Total distance travelled divided by time taken
Total distance (in metres)= 80+125+45=250
Total time (minutes) =10
250/10
=25
Thus Mary's average speed is 25 metres per minute.
6 0
4 years ago
Read 2 more answers
Two semiconductors are identical except that one has a band gap of 1.2 eV, while the other has a band gap of 1.1 eV. The room te
solong [7]

To solve this problem it is necessary to apply the relationship given by the intrinsic carrier concentration, in each of the phases.

The intrinsic carrier concentration is the number of electrons in the conduction band or the number of holes in the valence band in intrinsic material. This number of carriers depends on the band gap of the material and on the temperature of the material.

In general, this can be written mathematically as

\eta_i = \sqrt{N_cN_v}e^{-\frac{E_g}{2KT}}

Both are identical semiconductor but the difference is band gap which is:

E_{g1} = 1.1eV

n_{i1} = 1*10^{19}m^{-3}

E_{g2} = 1.2eV

T=300K

The ratio between the two phases are given as:

\frac{\eta_{i1}}{\eta_{i2}} = \frac{e^{-\frac{E_{g1}}{2KT}}}{e^{-\frac{E_{g2}}{2KT}}}

\frac{\eta_{i1}}{\eta_{i2}} = e^{\frac{E_{g2}-E_{g1}}{2KT}}

\frac{\eta_{i1}}{\eta_{i2}} =e^{\frac{(1.2-1.1)(1.6*10^{-19})}{2(1.38*10^{-23})(300)}}

\frac{\eta_{i1}}{\eta_{i2}} =e^{-1.932367}

\frac{\eta_{i1}}{\eta_{i2}} =0.145

Therefore the ratio of intrinsic carrier densities for the two materials at room temperature is 0.145

7 0
4 years ago
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