Which of the following is NOT a good example of a short-term goal?

A motorboat sets out for open sea. From home it travels 5 km due East, then heads [N35E] at 2 m/s for 90 minutes. After a break,

geniusboy [140]

The distance of the motorboat relative to the home, which travels in various directions, is 3.07 km.

<h3>What is relative velocity?</h3>

Relative velocity is a velocity of an object which is in respect to another observer, or it is a ratio of change in the position of a point to time with respect to another observer.

Given: Travel in East direction ( $d_{E}$ )= 5 km,

velocity in N35E(v) = 2 m / s, time taken(t) = 90 min = 5400 seconds,
Displacement in south ( $D_S}$ ) = 6.5 km

Firstly, find the displacement in N35E so

Displacement = Velocity × time,

$d_{NE}$ = 2 × 5400 = 10800 meters or 10.8 km

Now by using Pythagoras' theorem
We can calculate the return displacement in the south direction( $d_{S}$ ),

$d_{S}$ = $\sqrt{d^{2} _{NE}- d^{2} _{E } }$
$d_{S}$ = $\sqrt{10.8^{2}-5^{2} }$

$d_{S}$ = 9.57 km

Therefore, the distance of the boat from the home (D) = $d_S}$ - $D_S}$

D = 9.57 - 6.5;

D = 3.07 Km

To know more about Relative velocity:

brainly.com/question/19260269

#SPJ1

3 0

1 year ago

A 410-kg piano is being unloaded from a truck by rolling it down a ramp inclined at 25°. There is negligible friction and the ra

SpyIntel [72]

Answer:BOONK GANG

Explanation:

AHAHAHA I USE CALC LIKE IN CLASS AHAHA

5 0

4 years ago

Compare the magnitude of the electromagnetic and gravitational force between two electrons separated by a distance of 2.00 m. As

Lesechka [4]

First you need to know about two laws, which are:
1) Coulomb's law
2) Newton's law of gravitation

1.
According to Coulomb's law, Electric force between TWO charges is:
$F_{e} = \frac{k*q_{1}*q_{2}}{r^{2}}$ -- (A)

Where, k = 1/(4*π*epsilon_not) = $9 * 10^{9}$ $\frac{Nm^{2}}{C^{2}}$

Both $q_{1}$ and $q_{2}$ = -1.61 x $10^{-19}$ C
r = Distance between the two charges = 2.00m

Plug-in the above values in (A), you would get:

$F_{e}$ = (9 * $10^{9}$ ) (1.61 * $10^{-19}$ * 1.61 * $10^{-19}$ ) / (2*2)

$F_{e}$ = $5.83* 10^{-29}$ N

2.
According to Newton's law of gravitation:
$F_{g} = \frac{Gm_{1}m_{2}}{r^{2}}$ -- (B)

Where G = Gravitational constant = 6.674 * $10^{-11} m^{2} kg^{-1}s^{-2}$

m1 = m2 = Mass of the electron = $9.11 * 10^{-31}$ kg
r = 2.0 m

Plug-in the above values in (B), you would get:

$F_{g}$ = (6.674 * $10^{-11}$ ) ( $9.11 * 10^{-31}$ * $9.11 * 10^{-31}$ }[/tex]) / (2*2)

$F_{e}$ = $5.83* 10^{-29}$ N

$F_{e}$ = $1.38 * 10^{-71} N$

Now do Fe over Fg, you would get:
$\frac{F_{e}}{F{g}} = 4.23 * 10^{42}$

Ans: So the blanks are:
1) 5.82
2) 1.38
3) 4.23

-i

6 1

3 years ago

Read 2 more answers

In air, the 57 GHz radio wave has a shorter<br> wavelength compared to the 64 GHz radio wave.

dalvyx [7]

Answer:

False

Explanation:

Higher frequency signals have shorter wavelengths. Hence, the 64 GHz signal will have a shorter wavelength than the 57 GHz signal.

Frequency and wavelength are inversely proportional meaning as frequency increases wavelength decreases and as frequency decreases wavelength increases.

Cheers.

6 0

3 years ago

You are riding a bicycle. You apply a forward force of 150 N, and you and the bicycle have a combined mass of 90 kg. What is the

Ymorist [56]

<u>Answer</u>

1.667 m/s²

Using the Newton's second law of motion;

force is directly proportional to the rate of change of momentum and it takes place in the direction of force.

i.e F = change in momentum

F = (mv - mu)/t

=m(v-u)/t

= ma

∴ F =ma

a = F/m

= 150/90

= 1.667 m/s²

4 0

3 years ago