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Rama09 [41]
3 years ago
8

Which of the following is NOT a good example of a short-term goal?

Physics
1 answer:
Molodets [167]3 years ago
5 0
Loose 10 pounds im pretty sure
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The velocity of a passenger relative to a boat is -vpb. The velocity of the boat relative to the river it is moving on is vbr. T
RideAnS [48]

Answer:

vps = vbr + vrs - vpb

Explanation:

  • If the passenger were at rest, his speed relative to the shore will be identical to the boat's, as follows:
  • vps = vbr + vrs
  • As he is moving in a direction opposite to the boat's, his velocity relative to the shore must be less than if he were at rest, in the same quantity that he was moving opposite to the boat, as follows:
  • vps = vbr+ vrs -vpb
5 0
2 years ago
If there are two photons with different energies, the one that has a higher energy (a) has the higher frequency (b) has the high
kozerog [31]

Answer:

(a) has the highest frequency

Explanation:

E = hf...where E(is the energy of a photon);h(is the planck's constant) and f is the frequency of the photon

Whereby this formula shows us that energy of a photon is directly proportional to its frequency

So hence if the energy is high then the frequency of the photon is also high

3 0
3 years ago
How can parents help children to gain friends?
Andre45 [30]

Answer:

You could try finding a familiar peer to join the activity with your child. Or ask your child who their friends are at school, or what they look for in a friend at school.

7 0
3 years ago
Read 2 more answers
Suppose a wheel with a tire mounted on it is rotating at the constant rate of 2.83 times a second. A tack is stuck in the tire a
timama [110]

Answer:

The tangential speed of the tack is 6.988 meters per second.

Explanation:

The tangential speed experimented by the tack (v), measured in meters per second, is equal to the product of the angular speed of the wheel (\omega), measured in radians per second, and the distance of the tack respect to the rotation axis (R), measured in meters, length that coincides with the radius of the tire. First, we convert the angular speed of the wheel from revolutions per second to radians per second:

\omega = 2.83\,\frac{rev}{s} \times \frac{2\pi\,rad}{1\,rev}

\omega \approx 17.781\,\frac{rad}{s}

Then, the tangential speed of the tack is: (\omega \approx 17.781\,\frac{rad}{s}, R = 0.393\,m)

v = \left(17.781\,\frac{rad}{s} \right)\cdot (0.393\,m)

v = 6.988\,\frac{m}{s}

The tangential speed of the tack is 6.988 meters per second.

7 0
3 years ago
Como foi a despedida do bilhete?​
Dmitrij [34]
Can you translate to english ?
8 0
3 years ago
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