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miskamm [114]
3 years ago
6

Molecular iodine, i2(g), dissociates into iodine atoms at 625 k with a first-order rate constant of 0.271 s−1. part a part compl

ete what is the half-life for this reaction?
Chemistry
1 answer:
allochka39001 [22]3 years ago
4 0

Answer:

2.775 s.

Explanation:

<em>The half-life time for a first order reaction = 0.693 / k.</em>

Where, k is the rate constant of the reaction.

∴ The half-life time = <em>0.693 / k</em> = (0.693) / (0.271 s⁻¹) = 2.775 s.

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