Answer:
a.) 96000 g
b.) 0.00015 kL
c.) 18.8 L
d.) 36 KM
e.) -39.15 C
f.) 109.4 F
Explanation:
To turn kg to g, multiply the value by 1000
To Turn CL to KL, divide the volume value by 10000
To turn dl to l, divide volume by 10
to turn m to km, multiply meter value by 0.001 or divide by 1000
To convert c to f, multiply the temperature in degrees Celsius by 2, and then add 30
i hope this helps : )
Answer:
density.
Explanation:
A cubic centimeter of water weighs 1 gram. Since a cubic centimeter of vegetable oil weighs less than 1 gram, oil will float on water. Corn syrup is more dense than water so 1 cubic centimeter of corn syrup weighs more than 1 gram. Therefore, corn syrup sinks in water.
Hey there!
Here is your answer:
<u><em>The proper answer to this question is option D "sec-butyl bromide".</em></u>Reason:
<u><em>S</em></u><span><u><em>ec-butyl bromide looks often like this:</em></u>
<em>Therefore the answer is option D!</em>If you need anymore help feel free to ask me!
Hope this helps!
~Nonportrit</span>
Answer:
ask a question
Explanation:
You have to ask a question or solve a problem before you can develop a prediction/hypothesis, conduct an experiment or even make a conclusion. The question comes first.
Answer:
Here's what I get
Explanation:
The three resonance forms of N₂O are shown in the first diagram below (you can also use horizontal dashes to represent the bonding pairs).
To get the formal charge (FC) on the atoms, cut each bond in half, as in the second diagram.
Each atom gets the electrons on its side of the cut.
Formal charge = valence electrons in isolated atom - electrons on bonded atom
FC = VE - BE
(a) In Structure A
Left-hand N:
VE = 5
BE = 1 lone pair (2)+ 3 bonding electrons = 2 + 3 = 5
FC = 5 - 5 = 0.
Central N:
VE = 5
BE = 4
FC = 5 - 4 = +1
On O:
VE = 6
BE = 3 lone pairs(6) + 1 bonding electron = 7
FC = 5 - 6 = -1
(b) In Structure B
Left-hand N:
VE = 5
BE = 2 lone pairs (4)+ 2 bonding electrons = 4 + 2 = 6
FC = 5 - 6 = -1.
Central N:
VE = 5
BE = 4
FC = 5 - 4 = +1
On O:
VE = 6
BE = 2 lone pairs(4) + 2 bonding electrons = 6
FC = 6 - 6 = 0
(c) In Structure C
Left-hand N:
VE = 5
BE = 3 lone pairs (6)+ 1 bonding electrons = 6 + 1 = 7
FC = 5 - 7 = -2.
Central N:
VE = 5
BE = 4
FC = 5 - 4 = +1
On O:
VE = 6
BE = 1 lone pair(2) + 3 bonding electrons = 5
FC = 6 - 5 = +1