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algol [13]
2 years ago
8

State the property of a conducting wire which is utilised in making electric fuse.

Chemistry
1 answer:
Aleonysh [2.5K]2 years ago
8 0
The low melting point of the wire is utilized in making electric fuse.
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Why was mass lost from the crucible during the reaction?
Alexxandr [17]
If the crucible wasn't covered with a lid the reactants may have produced a gas that was released into the surroundings, or mass may have been lost in the form of water vapour.
6 0
2 years ago
I need help on this organic chemistry question:
Dvinal [7]
Selfmade.ivyy hope this help
7 0
3 years ago
1. Mixing is a physical change.<br> True or false
Hitman42 [59]

Answer:

true

Explanation:

if u mix it can explode which is a chemical reaction

5 0
2 years ago
Read 2 more answers
Dalton's law of partial pressures states that the total pressure exerted by a mixture of gases is the sum of the pressures exert
Damm [24]

Answer: The given statement is true.

Explanation:

According to the Dalton's law, total pressure of a mixture of gases that do not react with each other is equal to the partial pressure exerted by each gas.

The relationship is as follows.

          p_{total} = \sum_{i=1}^{n} p_{i}

or,        p_{total} = p_{1} + p_{2} + p_{3} + p_{4} + ......... + p_{n}

where,  p_{1}, p_{2}, p_{3} ....... = partial pressure of individual gases present in the mixture

Also, relation between partial pressure and mole fraction is as follows.

                 p_{i} = p_{total} \times x_{i}

where,      x_{i} = mole fraction

Thus, we can conclude that the statement Dalton's law of partial pressures states that the total pressure exerted by a mixture of gases is the sum of the pressures exerted independently by each gas in the mixture, is true.              

5 0
3 years ago
For a phase change, H0 = 2 kJ/mol and A S0 = 0.017 kJ/(K•mol). What are
34kurt

Answer:

ΔG = -6.5kJ/mol at 500K

Explanation:

We can find ΔG of a reaction using ΔH, ΔS and absolute temperature with the equation:

ΔG = ΔH - TΔS

Computing the values in the problem:

ΔG = ?

ΔH = 2kJ/mol

T = 500K

And ΔS = 0.017kJ/(K•mol)

Replacing:

ΔG = 2kJ/mol - 500K*0.017kJ/(K•mol)

ΔG = 2kJ/mol - 8.5kJ/mol

<h3>ΔG = -6.5kJ/mol at 500K</h3>

8 0
2 years ago
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