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3 years ago

A buffer solution is prepared by adding NH4Cl to a solution of NH3 (ammonia). what happens if NaOH is added?

Chemistry

1 answer:

mixer [17]3 years ago

6 0

Answer: The reaction proceeds in the backward direction.

Explanation:

A buffer is a solution that maintains the pH of the solution and resists any significant changes of pH on the addition of acid or alkali.

A buffer solution of $NH_4Cl\text{ and }NH_3$ is prepared. It is a basic buffer as it is formed by the combination of a weak base $(NH_3)$ and its conjugate acid $(NH_4Cl)$

When a strong base (NaOH) is added to this buffer solution, the ammonium ions releases hydrogen ion to the solution which then combines with the hydroxide ions to form water and ammonia in a solution. Thus, maintaining the pH of the buffer.

The given chemical equation follows:

$NH_3(aq)+H_2O(l)\rightleftharpoons NH_4^+(aq)+OH^-(aq)$

Hence, the reaction will proceed in the backward direction.

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20 How do you solve this ?

Kaylis [27]

Answer:

eight oxygen atoms

Explanation:

This formula shows that in one mole of this compound, there are 3 moles of Ca atoms that combine with 2 moles of the PO4(phosphate) groups, which gives a total of 2 moles of P atoms and 8 moles of 0 atoms.

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2 years ago

An aqueous solution of sucrose (C12H22O11C12H22O11) is prepared by dissolving 7.6330 gg in sufficient deionized water to form a

Mariana [72]

Answer:

The answer to your question is 0.64 M

Explanation:

Data

Sucrose C₁₂H₂₂O₁₁ mass = 7.633 g

volume = 25 ml

Molarity = ?

Process

1.- Calculate the molar weight of Sucrose

C₁₂H₂₂O₁₁ = (12 x 12) +(22 x 1) + (11 x 16)

= 144 + 22 + 176

= 342 g

2.- Calculate the moles of sucrose

342 g ------------------ 1 mol

7.633 g --------------- x

x = (7.633 x 1) / 342

x = 0.0223 moles

3.- Calculate the molarity

Molarity = moles / volume (L)

Molarity = 0.0223 / 0.035

Molarity = 0.64

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3 years ago

A reaction that is second-order in one reactant has a rate constant of 1 × 10–2 L/mol · s. If the initial concentration of the r

Harlamova29_29 [7]

Answer : It take time for the concentration to become 0.180 mol/L will be, 277.8 s

Explanation :

The integrated rate law equation for second order reaction follows:

$k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)$

where,

k = rate constant = $1\times 10^{-2}mol/L.s$

t = time taken = ?

[A] = concentration of substance after time 't' = 0.180 mol/L

$[A]_o$ = Initial concentration = 0.360 mol/L

Putting values in above equation, we get:

$1\times 10^{-2}=\frac{1}{t}\left (\frac{1}{0.180}-\frac{1}{0.360}\right)$

$t=277.8s$

Hence, it take time for the concentration to become 0.180 mol/L will be, 277.8 s

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3 years ago

Hydrogen can be extracted from natural gas according to the following equilibrium.

antiseptic1488 [7]

Answer:

2.16x10⁻²

Explanation:

First, let's find out the molar concentrations of the reactants. The molar mass of CH4 is 16 g/mol, and of CO2 is 44 g/mol. The number of moles is the mass divided by the molar mass:

nCH4 = 24.0/16 = 1.5 moles

nCO2 = 88.0/44 = 2 moles

The concentration is the number of moles divded by the volume, thus:

[CH4] = 1.5/1 = 1.50 M

[CO2] = 2/1 = 2.00 M

For the equilibrium reaction, let's do an equilibrium chart:

CH4(g) + CO2(g) ⇄ 2CO(g) + 2H2(g)

1.50 2.00 0 0 Initial

-x -x +2x +2x Reacts (stoichiometry is 1:1:2:2)

1.50-x 2.00-x 2x 2x Equilibrium

As sateted in problem, [CH4] = 2.70*[CO]

1.50 - x = 2.70*2x

1.50 - x = 5.4x

6.4x = 1.50

x = 0.2344

Thus, at equilibrium:

[CH4] = 1.50 - 0.2344 = 1.2656 M

[CO2] = 2.00 - 0.2344 = 1.7656 M

[CO] = 2*0.2344 = 0.4688 M

[H2] = 2*0.2344 = 0.4688 M

The equilibrium constant is the multiplication of the concentrations of the products elevated by their coefficients, divided by the multiplication of the concentration of the reactants elevated by their coefficients.

K = ([CO]²*[H2]²)/([CH4]*[CO2])

K = (0.4688²*0.4688²)/(1.2656*1.7656)

K = 0.0483/2.2345

K = 2.16x10⁻²

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3 years ago

What is the molarity of a solution that contains 152 g NaCl in 4.00 L solution?

Hunter-Best [27]

Answer:

200.0lg

Explanation:

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