Answer:
correct is d) a ’= g / 2
Explanation:
For this exercise let's use the kinematics equations
On earth
v = v₀ - a t
a = (v₀- v) / T
On planet X
v = v₀ - a' t’
a ’= (v₀-v) / 2T
Let's substitute the land values in plot X
a’= a / 2
Now let's use Newton's second law
W = ma
m g = m a
a = g
We substitute
a ’= g / 2
So we see that on planet X the acceleration is half the acceleration of Earth's gravity
Answer:
a) ![k_{avg}=6.22\times 10^{-21}](https://tex.z-dn.net/?f=k_%7Bavg%7D%3D6.22%5Ctimes%2010%5E%7B-21%7D)
b) ![k_{avg}=8.61\times 10^{-21}](https://tex.z-dn.net/?f=k_%7Bavg%7D%3D8.61%5Ctimes%2010%5E%7B-21%7D)
c) ![k_{mol}=3.74\times 10^{3}J/mol](https://tex.z-dn.net/?f=k_%7Bmol%7D%3D3.74%5Ctimes%2010%5E%7B3%7DJ%2Fmol)
d) ![k_{mol}=5.1\times 10^{3}J/mol](https://tex.z-dn.net/?f=k_%7Bmol%7D%3D5.1%5Ctimes%2010%5E%7B3%7DJ%2Fmol)
Explanation:
Average translation kinetic energy (
) is given as
....................(1)
where,
k = Boltzmann's constant ; 1.38 × 10⁻²³ J/K
T = Temperature in kelvin
a) at T = 27.8° C
or
T = 27.8 + 273 = 300.8 K
substituting the value of temperature in the equation (1)
we have
![k_{avg}=6.22\times 10^{-21}J](https://tex.z-dn.net/?f=k_%7Bavg%7D%3D6.22%5Ctimes%2010%5E%7B-21%7DJ)
b) at T = 143° C
or
T = 143 + 273 = 416 K
substituting the value of temperature in the equation (1)
we have
![k_{avg}=8.61\times 10^{-21}J](https://tex.z-dn.net/?f=k_%7Bavg%7D%3D8.61%5Ctimes%2010%5E%7B-21%7DJ)
c ) The translational kinetic energy per mole of an ideal gas is given as:
![k_{mol}=A_{v}\times k_{avg}](https://tex.z-dn.net/?f=k_%7Bmol%7D%3DA_%7Bv%7D%5Ctimes%20k_%7Bavg%7D)
here
= Avagadro's number; ( 6.02×10²³ )
now at T = 27.8° C
![k_{mol}=6.02\times 10^{23}\times 6.22\times 10^{-21}](https://tex.z-dn.net/?f=k_%7Bmol%7D%3D6.02%5Ctimes%2010%5E%7B23%7D%5Ctimes%206.22%5Ctimes%2010%5E%7B-21%7D)
![k_{mol}=3.74\times 10^{3}J/mol](https://tex.z-dn.net/?f=k_%7Bmol%7D%3D3.74%5Ctimes%2010%5E%7B3%7DJ%2Fmol)
d) now at T = 143° C
![k_{mol}=6.02\times 10^{23}\times 8.61\times 10^{-21}](https://tex.z-dn.net/?f=k_%7Bmol%7D%3D6.02%5Ctimes%2010%5E%7B23%7D%5Ctimes%208.61%5Ctimes%2010%5E%7B-21%7D)
![k_{mol}=5.1\times 10^{3}J/mol](https://tex.z-dn.net/?f=k_%7Bmol%7D%3D5.1%5Ctimes%2010%5E%7B3%7DJ%2Fmol)
almost everything artafitial would have been made because of science. However nothing natural would exist because of science. All science does is look around and see what's up.
The line is called equator.
Answer:
fo = 378.52Hz
Explanation:
Using Doppler effect formula:
![f'=\frac{C-Vb}{C-Va}*fo](https://tex.z-dn.net/?f=f%27%3D%5Cfrac%7BC-Vb%7D%7BC-Va%7D%2Afo)
where
f' = 392 Hz
C = 340m/s
Vb = 20m/s
Va = 31m/s
Replacing these values and solving for fo:
fo = 378.52Hz