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vredina [299]
3 years ago
13

What is the compare the strength of static,sliding,and rolling friction

Physics
1 answer:
Inga [223]3 years ago
7 0
The force needed to overcome sliding friction is more than the force needed to overcome rolling friction or static or even fluid 
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Which of the following represents a fully plastic collision? 1. Two billiard balls hit each other then move in opposite directio
Nutka1998 [239]

Answer:

Option (4)

Explanation:

There are two types of collision.

Perfectly elastic collision: the collision in which the momentum and kinetic energy is conserved. There is no loss of energy in other forms of energy.

Perfectly plastic collision: The collision in which the momentum is conserved and kinetic energy is not conserved. The two bodies stick after the collision.

Here, the bullet hits the block and then embedded in the block, it is the example of plastic collision.

3 0
3 years ago
You are waiting to turn left into a small parking lot. a car approaching from the opposite direction has a turn signal on. you s
katrin [286]
If the car in the opposite direction turns the signal on your vehicle, then it is only likely to give way and let him or her turn before you make your turn because he or she is in the right of way and by doing this, it will prevent any complication from happening and to be able to show respect and politeness in driving.
6 0
3 years ago
Two cars are heading towards one another. Car A is moving with an acceleration of aA = 4 m/s2. Car B is moving with an accelerat
Paladinen [302]

Answer:

Car B reaches car A in 19.7 s.

Explanation:

Hi there!

The equation of the position of an object moving in a straight line at constant acceleration is as follows:

x = x0 + v0 · t + 1/2 · a · t²

Where:

x = position of the object at time t.

x0 = initial position.

v0 = initial velocity.

t = time.

a = acceleration

When both cars meet, their positions are the same. At the meeting point:

position of car A = position of car B

xA = xB

x0A + v0A · t + 1/2 · aA · t² = x0B + v0B · t + 1/2 · aB · t²

Let´s place the origin of the frame of reference at the point where A is located. In that case x0A = 0 and x0B = 2900 m. Since both cars are initially at rest, v0A and v0B = 0. So, the equation gets reduced to this:

1/2 · aA · t² = x0B + 1/2 · aB · t²  

If we replace with the data we have and solve for t:

1/2 · 4 m/s² · t² = 2900 m - 1/2 · 11 m/s² · t²

2 m/s² · t² =  2900 m - 5.5 m/s² · t²

5.5 m/s² · t² + 2 m/s² · t² = 2900 m

7.5 m/s² · t² = 2900 m

t² = 2900 m / 7.5 m/s²

t = 19.7 s

Car B reaches car A in 19.7 s.

4 0
3 years ago
A copper bar of length h and electric resistance r slides with negligible friction on metal rails that have negligible electric
Elanso [62]
I think math is the best idea
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3 years ago
What makes human travel to the other planets in our solar system difficult?
inysia [295]

Answer:

Taking water and oxygen from Earth is rather expensive and hard to do.

Explanation:

Without water and oxygen, travel to other planets is basically impossible

4 0
3 years ago
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