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astraxan [27]
3 years ago
15

PLEASE HELP NEED ANSWER NOW!!!

Physics
1 answer:
Artist 52 [7]3 years ago
5 0

Answer:

the 3rd one

Explanation:

IT is 3rd one i have done it before

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A 15.7-g aluminum block is warmed to 53.2 °c and plunged into an insulated beaker containing 32.5 g of water initially at 24.5 °
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The equilibrium temperature of aluminium and water is 33.2°C

We know that specific heat of aluminium is 0.9 J/gm-K, and that of water is 1 J/gm-K

Now we can calculate the equilibrium temperature

(mc∆T)_aluminium=(mc∆T)_water

15.7*0.9*(53.2-T)=32.5*1*(T-24.5)

T=33.2°C

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