How many atoms are in 129 grams of calcium

How many milliliters of 0.25M H2SO4 can be prepared from 57 mL of a 3.0M solution of H2SO4?

DochEvi [55]

Answer:

Why ? Because 1 molecule of H2SO4 gives 2 H+ ions per molecule while only one H+ ion is required to neutralize 1 molecule of KOH. So, 1 molecule of H2SO4 can neutralize 2 molecules of KOH. Hence, we would require 525 ml of 0.03 M H2SO4 to neutralize 525 ml of 0.06 M KOH. How will we prepare 525 ml of 0.03 M H2SO4 ?

Explanation:

Now, we have 0.025 M H2SO4 and we do not know how much volume we have.

We will use the standard N1 X V1 = N2 X V2 for this calculation.

N1=0.025 M; V1=unknown; N2=0.03 M and V2=525 ml.

So V1= (0.03 X 525)/(0.025) = 630 ml.

5 0

3 years ago

An ice skater moves back and forth on an ice rink. She speeds up on the straight portion of the rink. She slows down near each e

andrey2020 [161]

The options are;

A) The skater experiences acceleration both while skating in a straight line and while making her turn.

B) Because the skater does not change her direction or speed, she does not experience acceleration.

C) The skater only experiences acceleration when she is turning.

D) The skater only experiences acceleration while skating in a straight line.

Answer:

A: The skater experiences acceleration both while skating in a straight line and while making her turn

Explanation:

We are told that She speeds up on the straight portion of the rink. This means that she experienced an acceleration since the speed was not constant but gradually increasing.

Also, we are told that She slows down near each end of the rink and then turns around. This means that she reduced speed before turning and it means there was also an acceleration as well when making the turn.

Thus, she experience acceleration both in the straight line and when making turn.

Option A is correct

6 0

3 years ago

Make a poem about compounds

OleMash [197]

Answer:

<h3>A Werewolf</h3>

___________

Poem with Compound Words

------------------------------------------

whenever there's a full moon,

I cannot overlook,

some alterations in my ways,

and changes in my look.

my werewolf hair grows everywhere,

my werewolf teeth get long,

my eyesight gets much keener and

I'm muscular and strong.

I get to roam around outside,

the moonlight makes me howl,

these otherworldly sound effects

mean I am on the prawl.

I see the moon is round and full,

I'm moonstruck by the sight,

I've made some telltale changes-so, you'd best stay in tonight.

Explanation:

I HOPE IT HELPS YOUR ENGLISH SUBJECT ;) ★

4 0

3 years ago

Which of the following gas samples would contain the same amount of gas as 200 mL of helium, He(g), at 25° C and 1 atm?

monitta

Answer:

$200\; \rm mL$ of neon $\rm Ne\, (g)$ at $25^{\circ} \rm C$ and $1\; \rm atm$ (the second choice) would contain an equal number of gas particles as $200\; \rm mL\!$ of $\rm He \, (g)$ at $25^{\circ} \rm C\!$ and $1\; \rm atm\!$ (assuming that all four gas samples behave like ideal gases.)

Explanation:

By Avogadro's Law, if the temperature and pressure of two ideal gases is the same, the number of gas particles in each gas would be proportional to the volume of that gas.

All four gas samples in this question share the same temperature and pressure. Hence, if all these gases are ideal gases, the number of gas particles in each sample would be proportional to the volume of that sample. Two of these samples would contain the same number of gas particles if and only if the volume of the two samples is equal to one another.

The second choice, $200\; \rm mL$ of neon $\rm Ne\, (g)$ at $25^{\circ} \rm C$ and $1\; \rm atm$ , is the only choice where the volume of the sample is also $200\; \rm mL \!$ . Hence, that choice would be the only one with as many gas particles as $200\; \rm mL\!$ of $\rm He \, (g)$ at $25^{\circ} \rm C\!$ and $1\; \rm atm\!$ .